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  • diany2020-11-21 14:33:28

      1. 定义函数解析电影评分和电影信息数据 def get_ratings_tuple(entry): items = entry.split('::') return int(items[0]), int(items[1]), float(items[2]) def get_movie_tuple(entry): items = entry.split('::') return int(items[0]), items[

  • laravel-admin 列的展开详细讲解2020-09-11 17:03:00

    use Encore\Admin\Widgets\Table; //必须写在控制器里 $grid->column('title', '标题')->expand(function ($model) {    //这里要让哪个字段显示下拉,就写哪个字段,没什么要求 $comments = $model->comments()->take(10)->get()->map(function ($comment) {

  • nvidia[单卡内部的调度原理]2020-09-10 14:01:34

    本人虽然研二开始接触cuda,但是终究未从事cuda开发,故而皆为零零散散的知识,虽然看了好几本cuda编程的书籍以及官网的文档(肯定没看全啊,我也不是专门从事cuda开发),市面上几乎都是关于如何cuda编程的书籍,而这些书籍中也看过不少《CUDA C编程权威指南》,《CUDA专家手册》,《CUDA并行程序设

  • Codeforces #656 Problem C2020-07-18 16:04:40

    题面 You are given an array a consisting of n integers. You have to find the length of the smallest (shortest) prefix of elements you need to erase from a to make it a good array. Recall that the prefix of the array a=[a1,a2,…,an] is a subarray consisting s

  • 210. Course Schedule II2020-06-30 22:04:59

    package LeetCode_210 import java.util.* import kotlin.collections.ArrayList /** * 210. Course Schedule II * https://leetcode.com/problems/course-schedule-ii/description/ * * There are a total of n courses you have to take, labeled from 0 to n-1. Som

  • 207. Course Schedule2020-06-30 21:53:14

    package LeetCode_207 import java.util.* import kotlin.collections.ArrayList /** * 207. Course Schedule * https://leetcode.com/problems/course-schedule/description/ * There are a total of numCourses courses you have to take, labeled from 0 to numCours

  • C. Mind Control2020-02-03 15:43:15

    链接:https://codeforces.com/contest/1291/problem/C You and your n−1n−1 friends have found an array of integers a1,a2,…,ana1,a2,…,an. You have decided to share it in the following way: All nn of you stand in a line in a particular order. Each minute

  • [LC] 207. Course Schedule2020-02-03 12:51:50

    There are a total of n courses you have to take, labeled from 0 to n-1. Some courses may have prerequisites, for example to take course 0 you have to first take course 1, which is expressed as a pair: [0,1] Given the total number of courses and a list o

  • 【2020.1.27】科比离开了。But Thank you, Kobe.2020-01-27 11:39:10

    “ 从第一次卷起父亲的直筒袜,我开始想象在球馆,投中制胜球的样子。 我明白了一件事,我已经爱上了你,篮球。 爱得如此之深,倾其所有。 从思想、身体,到精神、甚至灵魂。 一个六岁的孩子如此迷恋你, 爱之深,以至于看不到尽头。 向前飞奔,尽情跑遍每座球场,争取每一次球权。 我拼尽全力,

  • LightOJ - 1067 Combinations2020-01-22 15:42:36

      题目描述: Given n different objects, you want to take k of them. How many ways to can do it? For example, say there are 4 items; you want to take 2 of them. So, you can do it 6 ways. Take 1, 2 Take 1, 3 Take 1, 4 Take 2, 3 Take 2, 4 Take 3, 4 Input I

  • Take-home Final Project2020-01-02 18:54:09

    Take-home Final ProjectDue day: Jan 8, 2020December 16, 2019 The ?rst question is to estimate the multinomial Probit Model (MNP): Suppose thereare n consumers in the market, i = 1; 2; :::; n. Each of them makes comsumptiondecision according to her indire

  • python_面向对象——动态创建类2019-12-10 22:53:58

    # 给动态生产的类定义一个方法 def __init__(self,name): self.name = name print(self.name) def take(self,obj): print(obj) # 动态生成一个类type('类名',(父类1,父类2,),{字典:属性或方法}) Dog = type('Dog',(object,),{'age':22,'__init__':__ini

  • LINQ to SQL分组使用2019-10-23 22:04:58

    我有一个看起来像这样的表: Id GroupId Value 它大约有100行 如何返回前10行的值,但没有重复的GroupId?解决方法:应该这样做: var results = table .GroupBy(x => x.GroupId) .Select(x => new { Row = x, Value = x.Max(y => y.Value) }) .OrderByDescending(x => x.V

  • RxJava2 observable抛出UndeliverableException2019-09-30 04:03:23

    据我所知,RxJava2 values.take(1)创建另一个Observable,它只包含原始Observable中的一个元素.哪个不能抛出异常,因为它被take(1)的效果过滤掉,因为它发生在第二个. 如下面的代码片段所示 Observable<Integer> values = Observable.create(o -> { o.onNext(1);

  • C#中的Skip()和Take()2019-09-26 18:02:02

    Skip()和Take()方法都是IEnumerable<T> 接口的扩展方法,包括C#中的所有Collections类,如ArrayList,Queue,Stack等等,还有数组和字符串都可以调用这两个方法。 int[] test = { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 };test.Skip(i)表示从下标i开始截取,返回类型为IEnumerable<T>,返回的集合中

  • C# LINQ (2)2019-09-22 22:56:12

    Limiting Data —- Take() and Skip() 前面讲了 筛选 和 排序,现在讲 选取皇帝选妃,层层选拔,最后留几个,让他过目,他选一个或者几个作为妃子,大概是这么个意思Take(X) 是选取X个  Skip(Y) 是跳过前Y个 Select 选取子集 前面说的Where OrderBy 结果都是和原类型一样,弱水三千取一瓢,而

  • 2019银川网络赛2019-08-31 22:01:03

    比赛时通过:

  • 【c++回顾】3.1经典算法问题-混合背包问题2019-08-30 12:05:18

    问题描述: 给定n种物品和一个背包。物品i的重量是wi,其价值为vi,背包的容量为C。应该如何选择装入背包中的物品,使得装入背包中物品的总价值最大?每种物品有ni个或无限个 问题分析: 利用我的上一篇博客多重背包填满问题的程序,只需要将无限个物品的数量设置为INT_MAX即可 代码如下

  • English trip V2-B 19 How often is often? Teacher: GABRIELE2019-08-29 11:02:22

    In this lesson you will learn how to describe typical day.   课上内容(Lesson)   typical day  典型的一天 common day  普通的一天 normal day  平常的一天   annual leave  年度假;年休假 a daily routine  每天的例行公事;日常   On a typical day I usually tak

  • LeetCode-210. Course Schedule II2019-08-24 17:01:24

    There are a total of n courses you have to take, labeled from 0 to n-1. Some courses may have prerequisites, for example to take course 0 you have to first take course 1, which is expressed as a pair: [0,1] Given the total number of courses and a li

  • 2019CCPC秦皇岛站网络赛-1008-Fishing Master(贪心+思维)2019-08-23 20:01:03

    Fishing Master(贪心+思维) Problem Description Heard that eom is a fishing MASTER, you want to acknowledge him as your mentor. As everybody knows, if you want to be a MASTER’s apprentice, you should pass the trial. So when you find fishing MASTER eom, th

  • seek for|contrary to|lag behind|take up|take advantage of|be confident of|allow for |2019-08-18 18:54:56

    There are signs ________ restaurants are becoming more popular with families.  A. that  B. which  C. in which  D. whose 题目解析考查同位语从句。此句意思为:有迹象表明去餐馆用餐在家庭之中越来越流行。that引导同位语从句解释说明抽象名词sign,that不作成分,没

  • 1131 Subway Map (30 分)2019-08-09 09:03:59

    1131 Subway Map (30 分) In the big cities, the subway systems always look so complex to the visitors. To give you some sense, the following figure shows the map of Beijing subway. Now you are supposed to help people with your computer skills! Given the

  • 1.3.3 并发容器类MAP/LIST/SET/QUEUE2019-08-04 16:56:17

    HashMap 下标计算方法:hashCode & (length-1) ,&按位与操作,二进制相同位都是1,该位才为1 JDK1.7与JDK1.8中HashMap区别: JDK1.8在put元素时,若计算得到的下标下的链表长度达到8时(算上当前要加到链表尾部的元素),链表会转换成红黑树提高查找效率 ConcurrentHashMap 线程安全的HashMap JDK1.

  • 【2019.07.25 Python每日一题】答案 —— 反转字符串中的单词 III 【Leecode557】2019-07-27 20:35:29

    https://leetcode-cn.com/problems/reverse-words-in-a-string-iii/ 给定一个字符串,你需要反转字符串中每个单词的字符顺序,同时仍保留空格和单词的初始顺序。 示例 1: 输入: "Let's take LeetCode contest" 输出: "s'teL ekat edoCteeL tsetnoc" 注意:在字符串中,每个单词由单个

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