标签：207 Course graph Schedule numCourses course take item indegrees

package LeetCode_207

import java.util.*
import kotlin.collections.ArrayList

/**
 * 207. Course Schedule
 * https://leetcode.com/problems/course-schedule/description/
 *
There are a total of numCourses courses you have to take, labeled from 0 to numCourses-1.
Some courses may have prerequisites, for example to take course 0 you have to first take course 1,which is expressed as a pair: [0,1]
Given the total number of courses and a list of prerequisite pairs, is it possible for you to finish all courses?

Example 1:
Input: numCourses = 2, prerequisites = [[1,0]]
Output: true
Explanation: There are a total of 2 courses to take.

Example 2:
Input: numCourses = 2, prerequisites = [[1,0],[0,1]]
Output: false
Explanation: There are a total of 2 courses to take.
To take course 1 you should have finished course 0, and to take course 0 you should
also have finished course 1. So it is impossible.
 * */
class Solution {
    //bfs
    fun canFinish(numCourses: Int, prerequisites: Array<IntArray>): Boolean {
        val graph = ArrayList<ArrayList<Int>>()
        //create graph by prerequisites
        for (i in 0 until numCourses) {
            graph.add(ArrayList())
        }
        for (item in prerequisites){
            val start = item[1]
            val end = item[0]
            graph[start].add(end)
        }

        //calculate in degree
        val indegrees = IntArray(numCourses)
        for (g in graph){
            for (item in g){
                indegrees[item]++
            }
        }

        val queue = LinkedList<Int>()
        for (i in 0 until numCourses) {
            if (indegrees[i]==0){
                queue.offer(i)
            }
        }

        while (queue.isNotEmpty()){
            val cur = queue.poll()
            for (item in graph[cur]){
                indegrees[item]--
                if (indegrees[item]==0){
                    queue.offer(item)
                }
            }
        }

        for (i in 0 until numCourses){
            if (indegrees[i]!=0){
                //represent graph got a cycle, so return false
                return false
            }
        }

        return true
    }
}

标签：207,Course,graph,Schedule,numCourses,course,take,item,indegrees
来源： https://www.cnblogs.com/johnnyzhao/p/13216263.html

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