题意：求最小生成树最长边。 代码： 1 #include<stdio.h> 2 #include <algorithm> 3 #include <queue> 4 #include <math.h> 5 using namespace std; 6 #define ll long long 7 #define maxx 250005 8 #define inf 0x3f 9 const int mod=1e9+7; 10 //#defi
题目描述 1013 Battle Over Cities (25 分) It is vitally important to have all the cities connected by highways in a war. If a city is occupied by the enemy, all the highways from/toward that city are closed. We must know immediately if we need to repair a
It is vitally important to have all the cities connected by highways in a war. If a city is conquered by the enemy, all the highways from/toward that city will be closed. To keep the rest of the cities connected, we must repair some highways with the min
题目链接 题解： 由于我的方法和紫书不一样，所以专门写一下记录一下解题思路。 显然“\”和“/”两个方向的直线数量是相同的，所以我们考虑计算“/”方向的线的数量。 统计类问题，都需要找到合适的分类方法，使我们能够不重复、不遗漏的统计出所有情况。 本题我们以直线的起点分类，把直
1013 Battle Over Cities (25分) It is vitally important to have all the cities connected by highways in a war. If a city is occupied by the enemy, all the highways from/toward that city are closed. We must know immediately if we need to repair any o
1013 Battle Over Cities (25分) It is vitally important to have all the cities connected by highways in a war. If a city is occupied by the enemy, all the highways from/toward that city are closed. We must know immediately if we need to repair any other h
It is vitally important to have all the cities connected by highways in a war. If a city is conquered by the enemy, all the highways from/toward that city will be closed. To keep the rest of the cities connected, we must repair some highways with the mini
It is vitally important to have all the cities connected by highways in a war. If a city is occupied by the enemy, all the highways from/toward that city are closed. We must know immediately if we need to repair any other highways to keep the rest of the
#include<iostream> #include<cstdio> #include<cmath> #include<algorithm> using namespace std; const int maxn=800; int n,m,tot,u,v; int pre[maxn]; //存点 struct Point{ int x,y; }point[maxn]; //建边 struct Edge{ int a,b; do
1013 Battle Over Cities (25分) It is vitally important to have all the cities connected by highways in a war. If a city is occupied by the enemy, all the highways from/toward that city are closed. We must know immediately if we need to repair any ot
Highways Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 26772 Accepted: 7803 Special Judge Description The island nation of Flatopia is perfectly flat. Unfortunately, Flatopia has a very poor system of public highways. T
Highways Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 40303 Accepted: 17615 Description The island nation of Flatopia is perfectly flat. Unfortunately, Flatopia has no public highways. So the traffic is difficult in Flat
Highways Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 40303 Accepted: 17615 Description The island nation of Flatopia is perfectly flat. Unfortunately, Flatopia has no public highways. So the traffic is difficult in Flato
整理板子的时候翻出来的题，Kruskal板子题。 1 #include<cstdio> 2 #include<cstring> 3 #include<iostream> 4 #include<algorithm> 5 #include<cmath> 6 #include<string> 7 #include<stack> 8 #include<queue> 9 #include<vec
题目链接 题意： 二维坐标系上, 给出n个顶点的坐标, 有m个组顶点之间距离为0, 输出最小生成树中所有距离不为0的边的两点的坐标 题解： 裸最小生成树板子 只需要求出任意两点之间的距离即可 代码： #include<iostream>#include<stdio.h>#include<math.h>#include<algorithm>#includ
Highways POJ-1751 最小生成树 Prim算法 题意 有一个N个城市M条路的无向图,给你N个城市的坐标,然后现在该无向图已经有M条边了,问你还需要添加总长为多少的边能使得该无向图连通.输出需要添加边的两端点编号即可。 解题思路 这个可以使用最短路里面的Prim算法来实现，对于已经连接的
题目链接:http://poj.org/problem?id=1751Time Limit: 1000MS Memory Limit: 10000K Special Judge Description The island nation of Flatopia is perfectly flat. Unfortunately, Flatopia has a very poor system of public highways. The Flatopian government is aw
1013 Battle Over Cities （25 分) It is vitally important to have all the cities connected by highways in a war. If a city is occupied by the enemy, all the highways from/toward that city are closed. We must know immediately if we need to repair any other
1013 Battle Over Cities （25 分） It is vitally important to have all the cities connected by highways in a war. If a city is occupied by the enemy, all the highways from/toward that city are closed. We must know immediately if we need to repair any other hi
Highways 题目链接：https://vjudge.net/problem/SPOJ-HIGH Description: In some countries building highways takes a lot of time... Maybe that's because there are many possiblities to construct a network of highways and engineers can't make up their mind
It is vitally important to have all the cities connected by highways in a war. If a city is occupied by the enemy, all the highways from/toward that city are closed. We must know immediately if we need to repair any other highways to keep the rest of the
