输入一个二叉树的中序和后序遍历，请你输出一个叶子节点，该叶子节点到根的数值总和最小，且这个叶子是编号最小的那个。 输入： 您的程序将从输入文件中读取两行(直到文件结尾)。第一行是树的中序遍历值序列,第二行是树的后序遍历值序列。所有值将不同，大于零且小于或等于10000.二叉
Puzzle UVA - 227 A children’s puzzle that was popular 30 years ago consisted of a 5×5 frame which contained 24 small squares of equal size. A unique letter of the alphabet was printed on each small square. Since there were only 24 squares within the fr
原题链接 考察:记忆化搜索 思路: dfs模拟即可,用map判断当前数字出现过几次.但是回溯的时候要注意,如果本该有的数字没有说明被凑成了一对,但是恢复要恢复成1,如果有就要去掉这个数字. 本蒟蒻真的写得很繁琐,这位大佬利用位运算0 1的性质避免了判断2,很妙 GO
There is a funny car racing in a city with n junctions and m directed roads. The funny part is: each road is open and closed periodically. Each road is associate with two integers (a, b), that means the road will be open for a seconds, then closed for b
题目大意：如果两个人相互打电话（直接或间接），则说他们在同一个电话圈里。 分析：flyod传递闭包 #include <bits/stdc++.h> #define IOS ios::sync_with_stdio(false);cin.tie(0); using namespace std; typedef long long ll; const int MAXN = 25 + 5; vector<string> v;//储存
问题描述： 输入正整数 n n n,把整数 1 , 2 ,
In order to understand early civilizations, archaeologists often study texts written in ancient languages. One such language, used in Egypt more than 3000 years ago, is based on characters called hieroglyphs. Figure C.1 shows six hieroglyphs and their nam
You are to determine the value of the leaf node in a given binary tree that is the terminal node of a path of least value from the root of the binary tree to any leaf. The value of a path is the sum of values of nodes along that path. Input The input
Each year, fall in the North Central region is accompanied by the brilliant colors of the leaves on the trees, followed quickly by the falling leaves accumulating under the trees. If the same thing happened to binary trees, how large would the piles of
Before being an ubiquous communications gadget, a mobile was just a structure made of strings and wires suspending colourfull things. This kind of mobile is usually found hanging over cradles of small babies. The figure illustrates a simple mobile. I
Before being an ubiquous communications gadget, a mobile was just a structure made of strings and wires suspending colourfull things. This kind of mobile is usually found hanging over cradles of small babies. The figure illustrates a simple mobi
题意 计算1~n所有数的除1和这个数本身的约数的和。 \(n\le 2e9\) 题解 枚举每个数计算因数是\(O(n\sqrt{n})\)的，会超时。 考虑改成枚举因数，计算有多少个数是i的倍数，显然有\(\frac{n}{i}\)个。 每个因数对于答案的贡献为\(i * (\lfloor\frac{n}{i}\rfloor-1)\)（需要减去自身）。 这样
Most crossword puzzle fans are used to anagrams — groups of words with the same letters in different orders — for example OPTS, SPOT, STOP, POTS and POST. Some words however do not have this attribute, no matter how you rearrange their letters, you cann
Background from Wikipedia: “Set theory is a branch of mathematics created principally by the German mathematician Georg Cantor at the end of the 19th century. Initially controversial, set theory has come to play the role of a foundational theory in mode
Many areas of Computer Science use simple, abstract domains for both analytical and empirical studies. For example, an early AI study of planning and robotics (STRIPS) used a block world in which a robot arm performed tasks involving the manipulation of
You have devised a new encryption technique which encodes a message by inserting between its characters randomly generated strings in a clever way. Because of pending patent issues we will not discuss in detail how the strings are generated and inserted
A common typing error is to place the hands on the keyboard one row to the right of the correct position. So ‘Q’ is typed as ‘W’ and ‘J’ is typed as ‘K’ and so on. You are to decode a message typed in this manner. Input Input consists of s
Queues and Priority Queues are data structures which are known to most computer scientists. The Team Queue, however, is not so well known, though it occurs often in everyday life. At lunch time the queue in front of the Mensa is a team queue, for exa
//位运算 #include<iostream> #include<algorithm> #include<string> #include<map> #include<stdlib.h> using namespace std; typedef unsigned int uint; typedef long long ll; int main() { int m; while(~scanf("%d", &
Andy, 8, has a dream - he wants to produce his very own dictionary. This is not an easy task for him, as the number of words that he knows is, well, not quite enough. Instead of thinking up all the words himself, he has a briliant idea. From his book
UVa 548 - Tree 紫书例题 题意：给一棵点带权（权各不相同，都是正整数）二叉树的中序和后序遍历，找一个叶子使得它到根的路径上的权和最小。如果有多解，该叶子本身的权应尽量小 算法：递归建树，然后DFS。注意，直接递归求结果也可以，但是先建树的方法不仅直观，而且更好调试 思路 重点:后序遍
We have a machine for painting cubes. It is supplied with three different colors: blue, red and green. Each face of the cube gets one of these colors. The cube’s faces are numbered as in Figure 1. Since a cube has 6 faces, our machine can paint a f
好题。百思不得其解如何利用DFS获取一个图中的圈数，参考了一些博客，恍然大悟，思想很巧妙，利用连通图，将图分开几个部分，边缘就成了一部分，圈又成了一部分，只需要记录接壤的圈即可。 题目主要想教会coder的，就是抓住特征量的想法。 宁可一思进，莫在一思停。写代码原来就和打游戏一样，耐得住寂
#include <iostream> #include <istream> #include <sstream> #include <vector> #include <stack> #include <list> #include <map> #include <set> #include <deque> #include <queue> #include <cstring&g
DP思路，同时利用到了简单计算几何。 对于给定坐标计算面积的，推荐使用矢量叉积计算，此外，这道题需要考虑三角形各边是否是多边形对角线的情况（即凹多边形特殊情况） 事实上check函数并不严格判定这种连线是否落在多边形内的情况（一个凹多边形，内角大于180处三个连续点就是一种排查不出来的
