标签：case 万年历 int printf days 查询 break 理解 year
#include<stdio.h>
#define Mon 1
#define Tues 2
#define Wed 3
#define Thur 4
#define Fri 5
#define Sat 6
#define Sun 0
#define January_days 31
#define February_days 28
#define March_days 31
#define April_days 30
#define May_days 31
#define June_days 30
#define July_days 31
#define August_days 31
#define September_days 30
#define October_days 31
#define November_days 30
#define December_days 31
#define first1month January_days
#define first2month January_days+February_days
#define first3month January_days+February_days+March_days
#define first4month January_days+February_days+March_days+April_days
#define first5month January_days+February_days+March_days+April_days+May_days
#define first6month January_days+February_days+March_days+April_days+May_days+June_days
#define first7month January_days+February_days+March_days+April_days+May_days+June_days \
+July_days
#define first8month January_days+February_days+March_days+April_days+May_days+June_days \
+July_days+August_days
#define first9month January_days+February_days+March_days+April_days+May_days+June_days \
+July_days+August_days+September_days
#define first10month January_days+February_days+March_days+April_days+May_days+June_days \
+July_days+August_days+September_days+October_days
#define first11month January_days+February_days+March_days+April_days+May_days+June_days \
+July_days+August_days+September_days+October_days+November_days
int known_weekday = Tues;
int known_year = 1901;
int konwn_month = 1;
int known_day = 1;
int day_count(int month)
{
switch(month)
{
case 1: return 0;break;
case 2: return first1month;break;
case 3: return first2month;break;
case 4: return first3month;break;
case 5: return first4month;break;
case 6: return first5month;break;
case 7: return first6month;break;
case 8: return first7month;break;
case 9: return first8month;break;
case 10: return first9month;break;
case 11: return first10month;break;
case 12: return first11month;break;
}
}
char * month_name(int month)
{
switch(month)
{
case 1:
return "一月";
break;
case 2:
return "二月";
break;
case 3:
return "三月";
break;
case 4:
return "四月";
break;
case 5:
return "五月";
break;
case 6:
return "六月";
break;
case 7:
return "七月";
break;
case 8:
return "八月";
break;
case 9:
return "九月";
break;
case 10:
return "十月";
break;
case 11:
return "十一月";
break;
case 12:
return "十二月";
break;
default:
break;
}
}
/*按格式打印某年某月名称*/
void first_line_print(int month, int year)
{
//printf("%20s %d \n",month_name(month),year);
printf("%8d年 %s \n",year, month_name(month));
}
/*按格式打印星期名称*/
void week_print()
{
//printf("%-6s%-6s%-6s%-6s%-6s%-6s%-6s\n","Sun.", "Mon.", "Tues.", "Wed.", "Thur.", "Fri.", "Sat.");
printf("%-3s%-3s%-3s%-3s%-3s%-3s%-3s\n","日", "一", "二", "三", "四", "五", "六");
}
/*计算该年该月份与已知日子之间的距离天数*/
int date_distance_count(int month, int year)
{
int leap_year_count = 0;
int i;
int distance;
if (year > known_year)
{
for (i=known_year; i<year; i++)
{
if(((i%4 == 0) && (i%100 != 0) ) || (i%400 == 0))
{
leap_year_count++;
}
}
if (month > 2)
{
if(((year%4 == 0) && (year%100 != 0) ) || (year%400 == 0))
{
leap_year_count++;
}
}
}
else
if (year == known_year)
{
if (month > 2)
{
leap_year_count = 1;
}
}
distance = (year - known_year)*365 + leap_year_count + day_count(month);
return distance;
}
/*确定该月份第一天是星期几*/
int makesure_firstday_weekday(int month, int year)
{
int date_distance = 0;
int weekday;
date_distance = date_distance_count(month, year);
weekday = (known_weekday + date_distance)%7;
return weekday;
}
/*依次打印出该月份的日子*/
void print_in_turn(int month, int firstday, int year)
{
int i = 1;
int weekday;
switch(firstday)
{
case Sun:
break;
case Mon:
printf("%-3s","");
break;
case Tues:
printf("%-6s","");
break;
case Wed:
printf("%-9s","");
break;
case Thur:
printf("%-12s","");
break;
case Fri:
printf("%-15s","");
break;
case Sat:
printf("%-18s","");
break;
}
switch(month)
{
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
{
for(i=0; i<31; i++)
{
weekday = (firstday + i)%7;
printf("%-3d",i+1);
if(weekday == Sat)
{
printf("\n");
}
}
break;
}
case 2:
{
if(((year%4 == 0) && (year%100 != 0) ) || (year%400 == 0)) /*闰年*/
{
for(i=0; i<29; i++)
{
weekday = (firstday + i)%7;
printf("%-3d",i+1);
if(weekday == Sat)
{
printf("\n");
}
}
break;
}
else /*平年*/
{
for(i=0; i<28; i++)
{
weekday = (firstday + i)%7;
printf("%-3d",i+1);
if(weekday == Sat)
{
printf("\n");
}
}
break;
}
}
case 4:
case 6:
case 9:
case 11:
{
for(i=0; i<30; i++)
{
weekday = (firstday + i)%7;/*计算该天是星期几*/
printf("%-3d",i+1);
if(weekday == Sat)
{
printf("\n");/*如果是星期六，则换行*/
}
}
break;
}
}
}
void date_print(int month, int year)
{
int firstday;
firstday = makesure_firstday_weekday(month, year);
print_in_turn(month, firstday, year);
printf("\n");
}
void main_month(int month, int year)
{
first_line_print(month, year);
week_print();
date_print(month, year);
printf("\n\n");
}
void main_calendar(int year)
{
int i;
for(i=1; i<=12; i++)
{
main_month(i, year);
}
}
int main()
{
int year;
printf("请输入年份：year = ");
scanf("%d",&year);
printf("\n");
while(year < 1902)
{
printf("请输入大于1901的年份\n");
printf("请输入年份：year = ");
scanf("%d",&year);
printf("\n");
}
main_calendar(year);
scanf(" ");
return 0;
}
代码来源：https://www.jb51.net/article/51878.htm
万年历查询系统
这是一个简单的万年历查询系统，用户通过输入想要查询的年份可以查到该年的详细日历。
源代码里已经定义好了星期，月份，规定查询的年份大于1901，整个程序运用switch，case语句、循环嵌套语句和条件语句使整个程序运行成功并能显示日历。代码用Define规定好星期，月份的大小，每个月要加上上个月的天数，然后要考虑到闰年的特殊情况，利用条件语句计算如果是闰年就要加一天。
这个程序只会显示年份的日历，并不能详细查询某一天或者某一个月份，那么便可以自己参照这个程序，显示出某年某月的日历
代码如下：
void search_month(int year,int month)
{
int i=0,j,k=0,m; //j用于记录某月的第一天是星期几 m用于记录某月的天数 k用于换行提示
char x[10]=" ";
m=days_month(year,month);
j=someday(year,month,1);
//输出某月的日历
printf("------------------------------------------\n");
printf("%s\n",str);
for(;i<j;i++)
{
printf("%s",x);k++;
}
for(i=1;i<=m;i++)
{
k++;
if(k%7==0)
{
if(i<10)
{
printf(" %d ",i);
printf("\n");
}
else if(i>=10)
{
printf(" %d ",i);
printf("\n");
}
}
else
{
if(i<10)
{
printf(" %d ",i);
}
else if(i>=10)
{
printf(" %d ",i);
}
}
}
printf("\n------------------------------------------\n");
}
通过这段函数我们可以查询某一个月份的日历，使这个万年历程序更加完善。
标签：case,万年历,int,printf,days,查询,break,理解,year 来源： https://www.cnblogs.com/malajisi/p/10467392.html
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