ICode9

精准搜索请尝试: 精确搜索
首页 > 其他分享> 文章详细

模拟2048游戏

2021-10-13 14:01:58  阅读:199  来源: 互联网

标签:index01 square return matrix list 2048 merge 模拟 游戏


模拟2048游戏

import random
list_merge = None

square_matrix = [
    [0, 0, 0, 0],
    [0, 0, 0, 0],
    [0, 0, 0, 0],
    [0, 0, 0, 0],
]


def zero_to_end():
    """
    将所有元素去0,依次放置,末尾添加0
    :return:
    """
    for i in range(len(list_merge) - 1, -1, -1):
        if list_merge[i] == 0:
            del list_merge[i]
            list_merge.append(0)


def add():
    """
    计算两个相邻相同元素的和
    :return:
    """
    zero_to_end()
    for i in range(1, len(list_merge)):
        if list_merge[i] == list_merge[i - 1]:
            list_merge[i - 1] += list_merge[i]
            del list_merge[i]
            list_merge.append(0)


def left_move():
    """
    左移
    :return:
    """
    for line in square_matrix:
        global list_merge
        list_merge = line
        add()


def right_move():
    """
    右移
    :return:
    """
    for line in square_matrix:
        global list_merge
        list_merge = line[::-1]
        add()
        line[::-1] = list_merge


def up_move():
    """
    上移
    :return:
    """
    square_matrix_transpose(square_matrix)
    left_move()
    square_matrix_transpose(square_matrix)


def down_move():
    """
    下移
    :return:
    """
    square_matrix_transpose(square_matrix)
    right_move()
    square_matrix_transpose(square_matrix)


def square_matrix_transpose(squ_matrix):
    """
    方阵转置
    :param squ_matrix:
    :return:
    """
    for r in range(1, len(squ_matrix)):
        for c in range(r, len(squ_matrix[r])):
            squ_matrix[c][r - 1], squ_matrix[r - 1][c] = \
                squ_matrix[r - 1][c], squ_matrix[c][r - 1]


def play_game():
    """
    执行
    :return:
    """
    create_square_matrix()
    print_square()
    while True:
        execute_square_matrix()
        run = input("请输入要进行的操作:上移[W],下移[S],左移[A],右移[D]:").title()
        print_square()
        if run == "W":
            up_move()
        if run == "S":
            down_move()
        if run == "A":
            left_move()
        if run == "D":
            right_move()


def create_square_matrix():
    """
    首次生成方阵
    :return:
    """
    r_c_index01 = random.randint(0, 3)
    r_c_index02 = random.randint(0, 3)
    r_c_index03 = random.randint(0, 3)
    r_c_index04 = random.randint(0, 3)
    index01 = random.randrange(2, 5, 2)
    index02 = random.randrange(2, 5, 2)

    if r_c_index01 != r_c_index03 or r_c_index02 != r_c_index04:
        square_matrix[r_c_index01][r_c_index02] = index01
        square_matrix[r_c_index03][r_c_index04] = index02
    return square_matrix


def execute_square_matrix():
    """
    方阵随机添加一个元素
    :return:
    """
    r_c_index01 = random.randint(0, 3)
    r_c_index02 = random.randint(0, 3)
    index01 = random.randrange(2, 5, 2)
    if square_matrix[r_c_index01][r_c_index02] == 0:
        square_matrix[r_c_index01][r_c_index02] = index01
    else:
        square_matrix[r_c_index01][r_c_index02] = square_matrix[r_c_index01][r_c_index02]
    return square_matrix


def print_square():
    """
    以矩阵的形式输出
    :return:
    """
    for i in range(0, 4):
        print(square_matrix[i])


play_game()

标签:index01,square,return,matrix,list,2048,merge,模拟,游戏
来源: https://blog.csdn.net/m0_51634934/article/details/120742412

本站声明: 1. iCode9 技术分享网(下文简称本站)提供的所有内容,仅供技术学习、探讨和分享;
2. 关于本站的所有留言、评论、转载及引用,纯属内容发起人的个人观点,与本站观点和立场无关;
3. 关于本站的所有言论和文字,纯属内容发起人的个人观点,与本站观点和立场无关;
4. 本站文章均是网友提供,不完全保证技术分享内容的完整性、准确性、时效性、风险性和版权归属;如您发现该文章侵犯了您的权益,可联系我们第一时间进行删除;
5. 本站为非盈利性的个人网站,所有内容不会用来进行牟利,也不会利用任何形式的广告来间接获益,纯粹是为了广大技术爱好者提供技术内容和技术思想的分享性交流网站。

专注分享技术,共同学习,共同进步。侵权联系[81616952@qq.com]

Copyright (C)ICode9.com, All Rights Reserved.

ICode9版权所有