ICode9

精准搜索请尝试: 精确搜索
  • postgresql 合并函数 string_agg2022-07-20 16:31:43

    SELECT a.id,a.name as "companyName",a.xydm,a.fddbr,string_agg(case when d.zzlx = 1 then '路基路面'when d.zzlx = 2 then '桥梁'when d.zzlx = 3 then '隧道'when d.zzlx = 4 then '交通安全设施' end ||case when d.zzdj = 1 then

专注分享技术,共同学习,共同进步。侵权联系[81616952@qq.com]

Copyright (C)ICode9.com, All Rights Reserved.

ICode9版权所有