78. 子集 78. Subsets 题目描述 给定一组不含重复元素的整数数组 nums，返回该数组所有可能的子集（幂集）。 说明: 解集不能包含重复的子集。 每日一算法2019/6/6Day 34LeetCode78. Subsets 示例: 输入: nums = [1,2,3] 输出: [ [3], [1], [2], [1,2,3], [1,3],
题目链接： https://leetcode.com/problems/subsets/ 78： Given a set of distinct integers, nums, return all possible subsets (the power set). Note: The solution set must not contain duplicate subsets. 集合里面没有重复的，比如没有[1,2]和[2,1]，所以最好最好先对nums
题目链接：https://leetcode.com/problems/subsets/ 解题思路： 这里是经典回溯法解决问题，new ArrayList<>(item)这里是相当于new了一个新对象，不是在原始的对象上操作。 深度优先搜索 我会把所有的用回溯的题全部放在一起。 1 import java.util.ArrayList; 2 class Solution { 3
Given a collection of integers that might contain duplicates, nums, return all possible subsets (the power set). Note: The solution set must not contain duplicate subsets. Example:Input: [1,2,2]Output:[ [2], [1], [1,2,2], [2,2], [1,2], []] code1
Given a set of distinct integers, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example, If S =[1,2,3], a solution is: [ [3], [1], [2], [1
Given a set of distinct integers, nums, return all possible subsets (the power set). Note: The solution set must not contain duplicate subsets. Example: Input: nums = [1,2,3] Output: [ [3], [1], [2], [1,2,3], [1,3], [2,3], [1,2], [] ] class Solution {
目录 题目链接 注意点 解法 小结 题目链接 Subsets II - LeetCode 注意点 有重复的数字 数组可能是无序的，要先排序 解法 解法一：递归，只需要在Subsets中递归写法的基础上多加一句if(find(ret.begin(),ret.end(),tmp) == ret.end()) ret.push_back(tmp);j即可，因为已经排序了，所
Let's say given a number of array, you should print out, all the subet of this array. Example: [1, 2] Output: > "" > 1> 2 > 1,2 The number of subset should be 2^n... function print_set(subset) { if (subset.length === 0) {
Given a set of distinct integers, nums, return all possible subsets (the power set). Note: The solution set must not contain duplicate subsets. Example: Input: nums = [1,2,3] Output: [ [3], [1], [2], [1,2,3], [1,3], [2,3], [1,2], [
正解:折半搜索 解题报告: 传送门! 这题我开始看到的时候贼开心地就把这题的代码直接粘过来辣 然后就T辣,,,仔细思考一下,为什么呢? 因为会枚举到很多相同的状态 举个eg 20 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 那就考虑怎么改进? 因为想到,它枚举到了很多相同的状态 那我们就
/** * 78. Subsets * https://leetcode.com/problems/subsets/description/ * * Given a set of distinct integers, nums, return all possible subsets (the power set).Note: The solution set must not contain duplicate subsets.Example:Input: nums = [1,2,3]Output:[[
Given a set of distinct integers, nums, return all possible subsets (the power set). Note: The solution set must not contain duplicate subsets. Example: Input: nums = [1,2,3] Output: [ [3], [1], [2], [1,2,3], [1,3], [2,3], [1,2],
