题目来源：690. 员工的重要性 给定一个保存员工信息的数据结构，它包含了员工 唯一的 id ，重要度 和 直系下属的 id 。 比如，员工 1 是员工 2 的领导，员工 2 是员工 3 的领导。他们相应的重要度为 15 , 10 , 5 。 那么员工 1 的数据结构是 [1, 15, [2]] ，员工
壹 ❀ 引 本题来自LeetCode690. 员工的重要性，难度简单，题目描述如下： 给定一个保存员工信息的数据结构，它包含了员工 唯一的 id ，重要度 和 直系下属的 id 。 比如，员工 1 是员工 2 的领导，员工 2 是员工 3 的领导。他们相应的重要度为 15 , 10 , 5 。那么员工 1 的数据结构是 [1, 15,
""" # Definition for Employee. class Employee: def __init__(self, id: int, importance: int, subordinates: List[int]): self.id = id self.importance = importance self.subordinates = subordinates """
思路本质上就是广度优先搜索每遇到一个新节点，需要将其下属放到数组中，不断的遍历这个数组，更新重要度即可 class Solution { public: int getImportance(vector<Employee*> employees, int id) { if (employees.size() == 0) { return 0; }
给定一个保存员工信息的数据结构，它包含了员工 唯一的 id ，重要度 和 直系下属的 id 。 比如，员工 1 是员工 2 的领导，员工 2 是员工 3 的领导。他们相应的重要度为 15 , 10 , 5 。那么员工 1 的数据结构是 [1, 15, [2]] ，员工 2的 数据结构是 [2, 10, [3]] ，员工 3 的数据结构是
Problem Description There is a company that has N employees(numbered from 1 to N),every employee in the company has a immediate boss (except for the leader of whole company).If you are the immediate boss of someone,that person is your subordinate, and all
http://acm.hdu.edu.cn/showproblem.php?pid=3974 Assign the task Time Limit: 15000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 7144 Accepted Submission(s): 2708 Problem Description There is a company that has
690. Employee Importance Easy 377369FavoriteShare You are given a data structure of employee information, which includes the employee's unique id, his importance value and his direct subordinates' id. For example, employee 1 is the leader of
题目要求 You are given a data structure of employee information, which includes the employee's unique id, his importance value and his direct subordinates' id. For example, employee 1 is the leader of employee 2, and employee 2 is the leader of empl
