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  • pytorch学习笔记四:数据的预处理模块2022-02-08 23:36:49

    transforms是pytorch中常用的图像预处理方法,这个在torchvision计算机视觉工具包中。在安装pytorch时顺便安装了torchvision,在torchvision中,有三个主要的模块: ● torchvision.transforms:常用的图像预处理方法,比如:标准化、中心化、旋转、翻转等; ● torchvision.datasets:常用

  • 雪花算法通过顺序号持久化解决时钟回拨2022-02-08 17:02:21

    在雪花算法自定义解决时钟回拨问题一文中,对雪花算法的时钟回拨解决思路进行了说明,由于顺序号保存在内存中,每次启动都是从初始值开始,在特定场景下,比如停止服务后进行了时钟回拨,在理论上,还是可能出现序列号重复的情况。 这里将序列号持久化到本地磁盘文件中,这样下次启动时,首先会读

  • 题目翻译(23)2022-02-07 10:30:57

    Sequence Median(http://noi.openjudge.cn/ch0401/1625/) 描述 Given a sequence of N nonnegative integers. Let's define the median of such sequence. If N is odd the median is the element with stands in the middle of the sequence after it is sorted. One may

  • 专题测试二 树形结构 B - The Child and Sequence2022-02-07 01:02:26

    题目 At the children's day, the child came to Picks's house, and messed his house up. Picks was angry at him. A lot of important things were lost, in particular the favorite sequence of Picks. Fortunately, Picks remembers how to repair the sequenc

  • Duplicate Number(NOIOPJENGLISH19)2022-02-06 23:59:55

    Duplicate Number https://acs.jxnu.edu.cn/problem/NOIOPJENGLISH19 1000ms 65536K 描述: Given a sequence of N numbers, find a number A that the count of A in the sequence is at least two. 给出一列有n个数,找到数字a,a的数量在序列里倒数第二 输入: First line: one posi

  • 2022 简思短解2022-02-06 19:31:07

    273. 分级/CF13C Sequence/P2893 [USACO08FEB]Making the Grade G/P4331 [BalticOI 2004]Sequence 数字序列 273. 分级 | CF13C Sequence | P2893 [USACO08FEB]Making the Grade G | P4331 [BalticOI 2004]Sequence 数字序列

  • Sum is K(翻译)2022-02-06 15:02:00

    http://noi.openjudge.cn/english/15/ 描述 Given a sequence of N numbers. Find different numbers A and B in the sequence so that the sum of A and B equals to K. 输入 First line: two positive integers N (N <= 1000) and K (K <= 1000000). Second line: N posi

  • 微信小程序JavaScript函数中的异步操作顺序执行2022-02-03 21:31:57

    1.前言 小程序开发中经常遇到后一个操作依赖前一个操作异步执行结果的情形。虽然JavaScript是单线程语言,但是主线程中的耗时操作通常都被放入任务队列中异步执行,避免阻塞主线程,例如: let f1 = function (sequence) { console.log("f1开始执行"); setTimeout(function () {

  • UnicodeDecodeError: ‘gbk‘ codec can‘t decode byte 0x80 in position 540: illegal multibyte sequence2022-02-01 19:04:15

    错误:Python 3.7.1 (default, Dec 10 2018, 22:54:23) [MSC v.1915 64 bit (AMD64)] :: Anaconda, Inc. on win32 Type “help”, “copyright”, “credits” or “license” for more information. Failed calling sys.interactivehook Traceback (most recent call last):

  • PAT 1167 Cartesian Tree2022-02-01 19:02:30

    1167 Cartesian Tree (30 分) A Cartesian tree is a binary tree constructed from a sequence of distinct numbers. The tree is heap-ordered, and an inorder traversal returns the original sequence. For example, given the sequence { 8, 15, 3, 4, 1, 5, 12, 10, 1

  • 不通过删除重建方式,重置序列值的简单方法2022-01-28 07:31:09

    重置oracle序列从指定数字开始 declare n number(10); v_startnum number(10):=10000001;--从多少开始 v_step number(10):=1;--步进 tsql varchar2(200); v_seqname varchar2(200):='MIP_JF_SEQUENCE';--序列名 begin execute immediate 'select '||v_seqname||'.nextv

  • TCP三报文握手建立连接2022-01-25 22:35:24

       sequence /ˈsiːkwəns/     序号,顺序  三握手不多余:可以防止TCP连接请求延迟传送到TCP服务器后,产生错误;  

  • UVM入门与进阶学习笔记15——sequencer和driver2022-01-25 17:03:13

    目录 端口和方法事务传输过程分析(重点)通信时序 driver同sequencer之间的TLM通信采取get模式,即由driver发起请求,从sequencer一端获得item,再由sequencer将其传递至driver。作为driver,永远停不下来,只要它可以从sequencer获取item,它就一直工作。sequencer和item只应该在合

  • 『题解』Codeforces-438D The Child and Sequence2022-01-25 10:36:28

    D. The Child and Sequence Description 给定数列,区间查询和,区间取模,单点修改。 n , m ≤ 1

  • UVM-sequence,sequencer,driver2022-01-23 14:58:40

    package pack1; //pack1头 import uvm_pkg::*; //+UVM `include "uvm_macros.svh"//+工厂 class item extends uvm_sequence_item; rand int data_auto; rand int data_noauto; //声明两个data,一个加入自动化域,一个 //不加入 `uvm_object_utils_begin

  • sequence2022-01-21 20:31:08

    给定m个长度为n的序列 每个序列选一个数求和,求最小的n个 用堆来模拟搜索的过程 关键在于状态不重复 朴素写法: 用map来维护m个指针,判重 但是空间复杂度是\(mn^2\)的会爆 #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <queue> #in

  • 【uvm】uvm_event同步2022-01-21 19:02:44

    原文 篇10-uvm通信之uvm_event & uvm_event_pool & uvm_event_callback 参考资料 (1) UVM通信篇之六:同步通信元件(上) - 路科验证的日志 - EETOP 创芯网论坛 (原名:电子顶级开发网) - 1.同步的方法 (1) 在sv中,用于同步的方法有event, semaphore和mailbox; (2) 在UVM中,用于同步

  • 1.21我的五篇2022-01-21 18:02:20

    题目链接:https://acs.jxnu.edu.cn/problem/NOIOPJENGLISH03 题目:Magic Sequence 描述: Find a sequence of N numbers. Each number is equal to the count of (its index minus 1) in the sequence. 输入: One positive integer N (N <= 10). 输出: N lines: the i-th line contai

  • 为数不多的人知道的-Kotlin-技巧以及-原理解析(二),移动端跨平台开发大型项目2022-01-21 17:05:40

    使用 equals 方法并没有创建额外的对象,如果遇到需要比较字符串的时候,可以使用这种方法,减少额外的对象创建。 如何优雅的处理空字符串 当字符串为空字符串的时候,返回一个默认值,常见的写法如下所示: val target = “” val name = if (target.isEmpty()) “dhl” else target

  • pat甲级1029 Median2022-01-21 11:32:22

    Given an increasing sequence S of N integers, the median is the number at the middle position. For example, the median of S1 = { 11, 12, 13, 14 } is 12, and the median of S2 = { 9, 10, 15, 16, 17 } is 15. The median of two sequences is defined to be the

  • Java Scanner 无法正常读取文件2022-01-20 13:31:42

    Java Scanner 无法正常读取文件 问题 今天在测试程序时发现用Scanner读取文件时不能正常读取。代码如下: Scanner scanner = new Scanner(sourceFile);while (scanner.hasNext()) {    String str1 = scanner.nextLine(); 原因分析 通过查询源码,发现发MalformedInputException 就

  • PAT甲级1098 Insertion or Heap Sort (25 分)2022-01-20 12:06:08

    1098 Insertion or Heap Sort (25 分) According to Wikipedia: Insertion sort iterates, consuming one input element each repetition, and growing a sorted output list. Each iteration, insertion sort removes one element from the input data, finds the location

  • Sum is K2022-01-20 09:32:52

    描述: Given a sequence of N numbers. Find different numbers A and B in the sequence so that the sum of A and B equals to K. 输入: First line: two positive integers N (N <= 1000) and K (K <= 1000000). Second line: N positive integers (<= 1000000). 输出:

  • 英文题翻译32022-01-20 00:00:58

    Color Sequence  1000ms  65536K Color Sequence | JXNUOJ 描述 You are given a integer sequence c of length n, ci denotes the ith color in the sequence c. We define a color sequence is legal only if it merely contains colors that appear even number

  • 翻译2022-01-17 22:00:19

    Sum is K  1000ms  65536K 描述: Given a sequence of N numbers. Find different numbers A and B in the sequence so that the sum of A and B equals to K. 输入: First line: two positive integers N (N <= 1000) and K (K <= 1000000).Second line: N positive inte

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