思路 只需要不断取字典序最大的字符就可以了。 如何找字典序最大的字符：倒着查找，只要字符比后面所有的字符的字典序大或相等就做个记号，最后正着输出。 代码 #include<iostream> #include<cstdio> #include<algorithm> #include<cmath> #include<cstring> #include<string> using na
都是基础的pojo类的方法 get set方法 hashcode equals方法 toString方法 @Override public int compareTo(MessageQueue o) { { int result = this.topic.compareTo(o.topic); if (result != 0) { return result; } } {
题意 找一个串的最大字典序字串 题解 正序考虑会遇到无法确定这个数该不该选的情况，遇到的矛盾是无法确定后面有没有比它大的字母，所以我们只需要解决这个问题即可，做题时的基本思路就是正序不想试一试倒序能不能优化，我们可以记录住以i为结尾的最大字符然后第i-1个数与之比较，就
1 CF959D 构造 题目链接：https://codeforces.com/problemset/problem/959/d 2 题目描述 时间限制 \(3s\) | 空间限制 \(256M\) Mahmoud has an array a consisting of \(n\) integers. He asked Ehab to find another array \(b\) of the same length such that: \(b\) is l
链接：https://codeforces.com/contest/1281/problem/B Your friend Jeff Zebos has been trying to run his new online company, but it's not going very well. He's not getting a lot of sales on his website which he decided to call Azamon. His big problem,
int java.lang.String.compareTo(String anotherString) Compares two strings lexicographically（字典序; 按字典顺序;）. The comparison is based on the Unicode value of each character in the strings. The character sequence represented by this String object is compared
Give you a string with length N, you can generate N strings by left shifts. For example let consider the string “SKYLONG”, we can generate seven strings: String Rank SKYLONG 1 KYLONGS 2 YLONGSK 3 LONGSKY 4 ONGSKYL 5 NGSKYLO 6 GSKYLON 7
