mycode: class Solution { public: vector<int> sortedSquares(vector<int>& nums) { int n = 100000; int x = 0; for(int i=0;i<nums.size();i++){ if(abs(nums[i])<n){
方法一：先平方，再排序 时间复杂度：O(n+nlogn) => O(nlogn) Python class Solution: def sortedSquares(self, nums: List[int]) -> List[int]: for i in range(len(nums)): nums[i] = nums[i] ** 2 nums.sort() return nums Java class Sol
