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  • x86_64汇编基础:Basics2022-08-19 21:01:01

    参考 https://cs61.seas.harvard.edu/site/2018/Asm1/ 正文 Registers Registers are the fastest kind of memory available in the machine. x86-64 has 14 general-purpose registers and several special-purpose registers. This table gives all the basic registers, wit

  • C3.1 分支跳转-异常-系统指令2022-05-16 23:31:31

    C3.1.4 Exception generation and return   armv8提供了3中软件中断产生的异常和3中系统调用。系统调用允许软件主动地通过特殊指令请求更加高异常等级的程序所提供服务。       C3.1.5 System register instructions 在armv7中体系结构中,通过访问cp15协处理器访问系统寄存器

  • 归约指令Reduction Instructions2022-03-20 20:58:32

    归约指令Reduction Instructions 1、整数单宽度归约指令2、整数加宽归约指令3、浮点单宽度归约指令4、浮点加宽归约指令 归约指令的操作上一个是向量1中的元素0,另外一个是向量2,所以指令的后缀缩写为.vs,其实相当于一个标量加上向量2中的所有元素。 1、整数单宽度归约指令

  • Section One: Before the Great Dark Cloud2022-03-03 22:03:47

    Great Microprocessors of the Past and Present (V 13.4.0) (cpushack.com) Part I: The Intel 4004, the first (Nov 1971) . . The first single chip CPU was the Intel 4004, a 4-bit processor meant for a calculator. It processed data in 4 bits, but its instructi

  • Section Three: The Great Dark Cloud Falls: IBM's Choice.2022-03-03 17:03:29

    Great Microprocessors of the Past and Present (V 13.4.0) (cpushack.com) Part I: DEC PDP-11, benchmark for the first 16/32 bit generation. (1970) . . . . The DEC PDP-11 was the most popular in the PDP (Programmed Data Processors) line of minicomputers, a s

  • Section Seven: Weird and Innovative Chips2022-03-03 09:00:22

    Great Microprocessors of the Past and Present (V 13.4.0) (cpushack.com) Part I: Intel 432, Extraordinary complexity (1980) . . The Intel iAPX 432 was a complex, object oriented 32-bit processor that included high level operating system support in hardware

  • asm:as - gnu assembler2022-02-16 15:02:12

      as - gnu assembler   [root@rockylinux docs]#  man  as   AS(1) GNU Development Tools AS(1) NAME AS - the portable GNU assembler. SYNOPSIS as [-a[cdghlns][=file]] [--alternate] [-D]

  • 编程题:《语言解释器》2022-01-08 19:34:06

    一、语言解释器 描述: 实现一个简单的语言解释器,支持以下指令: 指令格式描述mov a v把数v赋值给a,其中a是变量名称,由不超过10个小写字母组成,v是变量名或者常数(常数为-10000~10000的整数)inc a变量a加1dec a变量a减1jnz a v如果变量a的值不是0,则相对跳转v条指令。比如-2,向上跳转两

  • [Leetcode 1041]机器人围成圈 Robot Bounded In Circle2021-11-28 01:03:51

    题目 机器人从(0,0)出发,初始化向北 三种指令 G当前方向+1步,L左转90度,R右转90度 问指令结束后是否成圆圈(只有可能回原点时才成圈) 返回true/false On an infinite plane, a robot initially stands at (0, 0) and faces north. The robot can receive one of three instructions: "

  • Robot Motion2021-11-12 20:02:39

    原题链接:http://acm.hdu.edu.cn/showproblem.php?pid=1035 Problem Description: A robot has been programmed to follow the instructions in its path. Instructions for the next direction the robot is to move are laid down in a grid. The possible instructions are N

  • ABB AC 900F学习笔记66:Freelance_Mounting_and_Installation_AC_900F_Controller-262021-08-17 14:03:04

    6 Wiring 布线 This section provides information on wiring the AC 900F controller exclusive of the CI/CM communication interface module. It contains safety instructions, general guidelines and information on cable routing 本节提供有关 AC 900F 控制器的布线信

  • [转载].NET Debugging Labs - Information and setup instructions2021-08-08 01:04:32

      LabChallengeInstructionsWalkthrough Lab 1: Performance Problem - Instructions Walkthrough Lab 2: Crash - Instructions Walkthrough Lab 3: High Memory Usage - Instructions Walkthrough Lab 4: High CPU Performance Problem - Instructions Walkthrou

  • [ASM教程]#6树API2021-07-16 10:32:16

    首发于Enaium的个人博客 使用树API来生成一个类 public static void main(String[] args) { ClassWriter classWriter = new ClassWriter(ClassWriter.COMPUTE_MAXS); ClassNode classNode = new ClassNode(); classNode.visit(V1_8, ACC_PUBLIC, "cn/enaium/learn/a

  • [ARM-assembly]-A64指令集合总结2021-06-21 14:55:26

    ★★★个人博客导读首页—点击此处 ★★★ A64指令集合总结 1、Instructions that move System or Special-purpose registers to or from a general-purpose register 2、Floating-point moves between a SIMD&FP register and a general-purpose register 3、SIMD moves bet

  • [ARM-register]-ARMv8的寄存器介绍2021-06-21 14:52:22

    ★★★ 友情链接 : 个人博客导读首页—点击此处 ★★★ 在介绍寄存器之前,我们先看下ARM中都有什么,以arm为例: 1、通用寄存器 (1)、 a r m

  • data race Comparing the performance of atomic, spinlock and mutex Spin-Locks vs. Atomic Instruction2020-12-21 08:02:14

      Spin-Locks vs. Atomic Instructions - Intel Community https://community.intel.com/t5/Intel-oneAPI-Threading-Building/Spin-Locks-vs-Atomic-Instructions/td-p/894992 c++ - Why is std::mutex faster than std::atomic? - Stack Overflow https://stackoverflow.com

  • cmake_host_system_information2020-12-15 14:33:32

    https://cmake.org/cmake/help/latest/command/cmake_host_system_information.html   Query host system specific information. cmake_host_system_information(RESULT<variable>QUERY<key>...) Queries system information of the host system on which c

  • [LeetCode] 1041. Robot Bounded In Circle2020-09-18 08:02:53

    On an infinite plane, a robot initially stands at (0, 0) and faces north.  The robot can receive one of three instructions: "G": go straight 1 unit; "L": turn 90 degrees to the left; "R": turn 90 degress to the right. The r

  • Instrction Arrangement UDH 4109 拓扑排序 or 最长路2020-05-01 18:57:16

    题目描述 Ali has taken the Computer Organization and Architecture course this term. He learned that there may be dependence between instructions, like WAR (write after read), WAW, RAW. If the distance between two instructions is less than the Safe Distance, i

  • Codeforces Round #605 (Div. 3) B. Snow Walking Robot(构造)2019-12-15 23:57:07

    链接: https://codeforces.com/contest/1272/problem/B 题意: Recently you have bought a snow walking robot and brought it home. Suppose your home is a cell (0,0) on an infinite grid. You also have the sequence of instructions of this robot. It is written as the

  • CSCM98, Assignment2019-12-01 18:53:56

    CSCM98, Assignment #1:Accelerating fractals (SIMD+MT)Important readingBy submitting this coursework, electronically and/or hardcopy, you state that you fully understand and arecomplying with the university's policy on Academic Integrity and Academic

  • HDU 1035 Robot Motion2019-11-09 11:50:45

    Robot Motion Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 3466    Accepted Submission(s): 1608 Problem Description A robot has been programmed to follow the instructions in its path. Instructi

  • 【关键路径】HDU4109 Instrction Arrangement2019-09-06 15:39:57

    Ali has taken the Computer Organization and Architecture course this term. He learned that there may be dependence between instructions, like WAR (write after read), WAW, RAW. If the distance between two instructions is less than the Safe Distance, it

  • LeetCode-1041. 困于环中的机器人2019-08-12 19:40:21

    在无限的平面上,机器人最初位于 (0, 0) 处,面朝北方。机器人可以接受下列三条指令之一: "G":直走 1 个单位 "L":左转 90 度 "R":右转 90 度 机器人按顺序执行指令 instructions,并一直重复它们。 只有在平面中存在环使得机器人永远无法离开时,返回 true。否则,返回 false。   示例

  • leetcode 1041 困于环中的机器人2019-07-29 09:36:20

    这个起始就是搞清楚机器人朝每个方向的运动步数就ok了,因为没有障碍物,所以只是需要统计方向和步数就行了。 ### 题目 在无限的平面上,机器人最初位于 (0, 0) 处,面朝北方。机器人可以接受下列三条指令之一: "G":直走 1 个单位 "L":左转 90 度 "R":右转 90 度 机器人按顺序执行指令

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