ICode9

精准搜索请尝试: 精确搜索
  • Codeforces Round #637 (Div. 2) - Thanks, Ivan Belonogov! B.Nastya and Door2020-04-25 20:01:15

    Codeforces Round #637 (Div. 2) - Thanks, Ivan Belonogov! B.Nastya and Door 题目链接 On February 14, Denis decided to give a Valentine to Nastya and did not come up with anything better than to draw a huge red heart on the door of the length k (k≥3). Na

  • CF776D The Door Problem2020-01-30 21:56:38

    考虑 \(\texttt{2-SAT}\) 首先每个门 \(i\) 都有一个初始状态 \(a_i\) 题目条件每个门只被两个开关控制,那么很显然的 \(\texttt{2-SAT}\) 用 \(b_{i,{0/1}}\)记录是第 \(1/2\) 个开关 然后就考虑一下门的初始状态 \(a_i\) 门本身是开的 你开这个开关为开,另一个也要是开的, 反之亦

  • 【转载】网易极客战记官方攻略-地牢-恐惧之门2019-12-23 18:53:01

    关卡连接: https://codecombat.163.com/play/level/dread-door 恐惧之门后藏满宝藏 简介: while-true 循环可以使用任何方法,如: while True:     hero.moveRight()     hero.attack("Brak") 默认代码 # 攻击大门(“Door”) # 需要攻击很多次,请使用"while-true"循环 概

  • Accelerate Games With Azure Front Door2019-11-30 18:01:48

    前段时间做了个游戏加速的项目,通过微软Azure Front Door为基于HTTP/HTTPS协议的休闲游戏加速,加速效果不错。                            

  • PKU-2723 Get Luffy Out(2-SAT+二分)2019-11-09 19:57:30

    Get Luffy Out 题目链接 Ratish is a young man who always dreams of being a hero. One day his friend Luffy was caught by Pirate Arlong. Ratish set off at once to Arlong's island. When he got there, he found the secret place where his friend was kept, but h

  • 对组件、Prop 和 State的研究-----------------引用2019-11-07 10:00:38

    组件 第一步是将 UI 分解成多个组件。例如,我们可以这样来拆分房子:        现在来编码! House:  <div>    <Roof />     // 房顶    <Wall />     // 墙    <Window />   // 窗    <Door />     // 门  </div>  等一下,怎么看起来这么像 HTML ?没错!React 的

  • 一道有意思的思维题2 --- 排序、枚举2019-09-30 20:02:56

        这道题是又一次在和学弟吃饭的路上听学弟讲的,感觉挺不错的^_^,这样仿佛经常听学弟讲题能收获不少呀,可能明年笔试有望了,哈哈~   Problem:     平面上给了有n个人,位置由(x,y)元组给定,平面上还有m扇门,位置由(x,y)给定。现在约定每扇门只能进一个人,且人只能向左和下移动(向

  • CF629E Famil Door and Roads【树上计数+分类讨论】2019-09-26 12:50:25

    Online Judge:Codeforces629E,Luogu-CF629E Label:树上计数,分类讨论,换根 题目描述 给出一棵n个节点的树。有m个询问,每一个询问包含两个数a、b,我们可以对任意两个不相连的点连一条无向边,并且使得加上这条边后a,b处在一个环内。对于每一个询问,求这样的环的期望长度。 \(2<=n,m<=10^5\)

  • B - The Festive Evening CodeForces - 834B2019-08-18 11:38:12

    It’s the end of July – the time when a festive evening is held at Jelly Castle! Guests from all over the kingdom gather here to discuss new trends in the world of confectionery. Yet some of the things discussed here are not supposed to be disclosed t

  • destUrl = destUrl + "/door_query/uploaditem.php";一次严重的bug2019-08-13 12:11:13

    在发送http请求时,我将destUrl 拼接目标接口后直接用destUrl接收了,因为destUrl是单例的,在整个上下文内只存在一个该实例,所以导致了destUrl形成了一个持续拼接的问题。

  • 纪中10日T3 2296. 神殿 bfs2019-08-11 20:01:42

    2296. 神殿  (File IO): input:temple.in output:temple.out 时间限制: 1500 ms  空间限制: 524288 KB  具体限制   Goto ProblemSet 题目描述 输入 输出 样例输入 样例输入12 2+**U1 1 2 2样例输入22 3<><><>1 1 2 1 样例输出 样例输出1-1样例输出24 数据范围限制

  • UOJ #492.单词游戏2019-07-15 14:00:23

    【题目描述】: 有 N 个盘子,每个盘子上写着一个仅由小写字母组成的英文单词。你需要给这些盘子安排一个合适的顺序,使得相邻两个盘子中,前一个盘子上单词的末字母等于后一个盘子上单词的首字母。请你编写一个程序,判断是否能达到这一要求。如果能,请给出一个合适的顺序。 【输入描述】:

  • cf---A. Amusing Joke2019-06-10 11:52:09

    So, the New Year holidays are over. Santa Claus and his colleagues can take a rest and have guests at last. When two “New Year and Christmas Men” meet, thear assistants cut out of cardboard the letters from the guest’s name and the host’s name in h

  • 状态模式——State 更好的实现状态机2019-05-01 11:56:34

                    1. 概述    The intent of the STATE pattern is to distribute state-specific logic across classes that represent an object’s state.    STATE 设计模式的目的 是:将特定状态相关的逻辑分散到一些类的状态类中。 2. 实例 

  • java接口基础知识2019-04-09 18:55:29

    接口:官方的含义是---->java接口是一系列方法的声明,是一些方法特征的集合疑问:那为什么不用抽象类呢?把他们共有的方法集合起来放在一个抽象类里面,同样可以调用哇,但是反过来想一想如果这些方法,不是同一个类,就比如飞这个方法,飞机有飞这个方法,蚊子有飞这个方法,如果让他连同时继承拥有飞

  • 【CF 1143A】The Doors2019-03-31 13:49:09

                                              A. The Doors Three years have passes and nothing changed. It is still raining in London, and Mr. Black has to close all the doors in his home in order to not be flooded. Once, however, Mr. Blac

  • A Dangerous Maze (概率期望)2019-02-11 13:37:55

    A Dangerous Maze  LightOJ - 1027  You are in a maze; seeing n doors in front of you in beginning. You can choose any door you like. The probability for choosing a door is equal for all doors. If you choose the ith door, it can either take you back to the

专注分享技术,共同学习,共同进步。侵权联系[81616952@qq.com]

Copyright (C)ICode9.com, All Rights Reserved.

ICode9版权所有