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  • color flip2022-07-10 08:34:01

    886. Possible Bipartition Medium We want to split a group of n people (labeled from 1 to n) into two groups of any size. Each person may dislike some other people, and they should not go into the same group. Given the integer n and the array di

  • 886. 可能的二分法2022-01-20 17:36:12

    给定一组 N 人(编号为 1, 2, ..., N), 我们想把每个人分进任意大小的两组。 每个人都可能不喜欢其他人,那么他们不应该属于同一组。 形式上,如果 dislikes[i] = [a, b],表示不允许将编号为 a 和 b 的人归入同一组。 当可以用这种方法将所有人分进两组时,返回 true;否则返回 false。 来

  • 886. Possible Bipartition2021-07-01 04:00:06

    Given a set of n people (numbered 1, 2, ..., n), we would like to split everyone into two groups of any size. Each person may dislike some other people, and they should not go into the same group.  Formally, if dislikes[i] = [a, b], it means it is not

  • LeetCode 886. Possible Bipartition?2020-11-30 12:58:09

    Given a set of N people (numbered 1, 2, …, N), we would like to split everyone into two groups of any size. Each person may dislike some other people, and they should not go into the same group. Formally, if dislikes[i] = [a, b], it means it is not allo

  • leetcode 886. 可能的二分法(DFS,染色,种类并查集)2020-11-21 21:02:36

    题目链接 886. 可能的二分法 题意: 给定一组 N 人(编号为 1, 2, ..., N), 我们想把每个人分进任意大小的两组。 每个人都可能不喜欢其他人,那么他们不应该属于同一组。 形式上,如果 dislikes[i] = [a, b],表示不允许将编号为 a 和 b 的人归入同一组。 当可以用这种方法将所有人分进两

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