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  • Codeforces Round #597 (Div. 2) A. Good ol' Numbers Coloring2019-11-05 12:52:23

    链接: https://codeforces.com/contest/1245/problem/A 题意: Consider the set of all nonnegative integers: 0,1,2,…. Given two integers a and b (1≤a,b≤104). We paint all the numbers in increasing number first we paint 0, then we paint 1, then 2 and so on. Each n

  • Black box2019-11-03 21:03:53

    #include<bits/stdc++.h>#define N 200005using namespace std;int m,n,k;int a[N],b[N],u[N];struct MM{ int l,r,s;}tree[N<<2];inline void build(int root,int L,int R){ tree[root].l=L; tree[root].r=R; if(L==R) return; int mid=(L+R)>

  • Aizu - 1382 Black or White (分段决策,单调队列优化dp)2019-10-17 12:00:55

    题意:给定只有黑白两种颜色的序列A,B,每次可以选择一段连续的长度不超过k的区间将其染成同一种颜色,求把序列A变成B所需的最小操作次数。 首先需要找出一些最优解的特征: 1.如果序列A的第一个颜色和B的相同,那么可以忽略掉。如果相反,那么必须将其染成相反的颜色。 2.最优解不会交叉,因为

  • Codeforces Round #587 (Div. 3) C - White Sheet2019-09-21 19:53:35

    原文链接:https://www.cnblogs.com/xwl3109377858/p/11564279.html Codeforces Round #587 (Div. 3) C - White Sheet There is a white sheet of paper lying on a rectangle table. The sheet is a rectangle with its sides parallel to the sides of the table. If you will t

  • 【CF375E】Red and Black Tree(线性规划)(单纯形)2019-09-17 14:41:29

    传送门 题解: 有一种复杂度优秀实际无比垃圾的O(n3)O(n^3)O(n3)树形DP,我以前写的:传送门 这里主要就是考虑线性规划,首先列出来,xix_ixi​表示这个点选没选,aia_iai​表示选择这个点为黑点的代价。 limits:∑i=1nxi=m∑dis(i,j)<Kxj≥1,∀ixi≥0minimize:∑iaixi \begin{aligne

  • 【POJ 1442 --- Black Box】大根堆和小根堆,优先队列2019-09-12 19:07:39

    【POJ 1442 --- Black Box】大根堆和小根堆,优先队列 Description Our Black Box represents a primitive database. It can save an integer array and has a special i variable. At the initial moment Black Box is empty and i equals 0. This Black Box processes a

  • Jquery选择器2019-09-08 21:06:51

    Jquery选择器: 1.基本选择器 2.层次选择器 3.类选择器 4.属性选择器 5.过滤选择器 1.基本选择器 标签选择器: $("html标签名"); //选中所有匹配标签名称的元素 $("div").css("backgroundColor","pink"); id选择器: $("#属性id的值"); //选中首个指定id的元素

  • 28-样式优先级2019-09-06 18:51:46

    <!DOCTYPE html><html lang="en"><head> <meta charset="UTF-8"> <title>Title</title> <link rel="stylesheet" href="25样式优先级.css"> <style> *{ m

  • Emoji 映射编码2019-09-04 12:57:24

    Emoji官网:https://emojipedia.org/ Name   Unified DoCoMo KDDI Softbank Google Wechat   black sun with rays U+2600 U+E63E U+E488 U+E04A U+FE000 ☀   cloud U+2601 U+E63F U+E48D U+E049 U+FE001 ☁   umbrella with rain drops U+2614 U+E640 U+E48C

  • python-matplotlib-annotate_添加图形内容细节指向2019-08-22 21:53:59

    import matplotlib.pyplot as pltimport numpy as npx=np.linspace(0.05,10,1000)y=np.sin(x)plt.plot(x,y,ls="-.",lw=2.3,color="black",label="sin()")plt.annotate("maxvalues",xy=(7.8,1.0),xytext=(4.5,0.9),weight="bol

  • [POJ - 1979]Red and Black2019-08-20 14:01:10

    典型迷宫。 #include<cstdio>#include <cstring>using namespace std;int m, n,cnt, count;char A[101][101];int direction[4][2]={{1,0},{0,1},{0,-1},{-1,0}};void dfs(int i, int j){ if(i < 0|| j < 0|| i >= m|| j >= n || (A[i][j] != '.&

  • 表格边框的合并2019-08-19 19:02:03

    表格边框合并之前: 表格外层与列之间默认有一定距离 做一些处理: <style type="text/css"> table{ width: 400px; margin: 0 auto; /* border: 1px solid black; */ /* table和td之间有一段默认的距离 通

  • POJ 1753 Flip Game (DFS)2019-08-14 20:54:22

    题目链接:POJ 1753 Problem Description Flip game is played on a rectangular 4x4 field with two-sided pieces placed on each of its 16 squares. One side of each piece is white and the other one is black and each piece is lying either it's black or white si

  • Halcon学习笔记(八)——OCR识别字符排列圆形或字体倾斜的处理办法2019-08-14 11:39:21

    在上一篇博客Halcon学习笔记(八)——OCR识别初步模板识别与生成训练文件中,我们着重分析了利用模板进行OCR识别并形成自己的训练文件的主要例程,下面我们分析,当字符排列是圆形或者字体倾斜时如何处理。 第三讲 呈圆形排列或倾斜字符的OCR识别 ocr_cd_print_polar_trans例程 圆

  • Red and Black2019-08-11 10:01:01

    Problem Description There is a rectangular room, covered with square tiles. Each tile is colored either red or black. A man is standing on a black tile. From a tile, he can move to one of four adjacent tiles. But he can't move on red tiles, he can mo

  • 1135 Is It A Red-Black Tree (30 分)2019-08-09 09:03:37

    1135 Is It A Red-Black Tree (30 分) There is a kind of balanced binary search tree named red-black tree in the data structure. It has the following 5 properties: (1) Every node is either red or black. (2) The root is black. (3) Every leaf (NULL) is bl

  • APT甲级——A1069 The Black Hole of Numbers2019-08-05 14:50:30

    For any 4-digit integer except the ones with all the digits being the same, if we sort the digits in non-increasing order first, and then in non-decreasing order, a new number can be obtained by taking the second number from the first one. Repeat in this

  • The 2018 ACM-ICPC Asia Qingdao Regional Contest, Online2019-08-04 15:03:10

    XOR Clique Press the Button Kuririn MIRACLE Traveling on the Axis Couleur Chaleur Infinite Parenthesis Sequence Pixel Art Halting Problem Red Black Tree Live Love

  • less基本用法2019-08-02 18:00:23

    在vue中使用less首先要下载依赖: npm install less less-loader --save-dev 下载好之后就可以.vue文件中使用lang="less"和@import 如下图: 1,将vue组件中style标签属性改为: <style lang="less" rel="stylesheet/less"></style> 2,如有引入文件,则文件后缀名必为.less 并以 @import

  • 在gazebo中建立环境和车辆模型(二)2019-08-02 17:44:15

    在gazebo中建立环境和车辆模型(二) 1.引言 在gazebo仿真工具中对机器人的物理性质(如:重力、阻力等)进行仿真。接上一节环境模型,这一节从机器人模型搭建、传感器插件添加。 本节参照下方教程。 https://blog.csdn.net/Hu_weichen/article/details/86682796 2.solidworks 建模 (1)注

  • python 类(3) property2019-08-02 11:56:20

    class PetCat(): """ 家猫类""" def __init__(self, name, age): self.name = name # 私有属性 self.__age = age @property def age(self): return self.__age @age.setter def age(self,value):

  • I - Red and Black DFS2019-07-24 23:51:39

    There is a rectangular room, covered with square tiles. Each tile is colored either red or black. A man is standing on a black tile. From a tile, he can move to one of four adjacent tiles. But he can't move on red tiles, he can move only on black til

  • 布朗运动与金融数学:百年征途2019-07-24 10:43:52

    作者: 郑连虎 来源:阿虎定量笔记 正文: 巴舍利耶:金融数学之父                             ——要点:布朗运动、有效市场假说 即使在信息爆炸的今天,想要了解法国数学家路易斯·巴舍利耶(Louis Bachelier,1870-1946)的生活,依然缺乏资料。同许多思想超前的开拓者一样,巴

  • B - Red and Black 直接BFS+队列2019-07-23 22:00:52

    There is a rectangular room, covered with square tiles. Each tile is colored either red or black. A man is standing on a black tile. From a tile, he can move to one of four adjacent tiles. But he can't move on red tiles, he can move only on black til

  • hdu3911 Black And White (线段树/区间合并)2019-07-19 22:37:19

    题目 n(n<=1e5)个数的数列,每个数只可能是0或1 m(m<=1e5)个操作,操作分两种 1 x y 代表 将[x,y]内所有数都取反 0 x y 询问 [x,y]内最长连续1的个数 思路来源 https://ac.nowcoder.com/discuss/206415?type=101&order=0&pos=1&page=1 吉首大学校赛 K-白山茶与红玫瑰 题解 如果

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