7-8 字符串的冒泡排序 （20 分) 我们已经知道了将N个整数按从小到大排序的冒泡排序法。本题要求将此方法用于字符串序列，并对任意给定的K（<N），输出扫描完第K遍后的中间结果序列。 输入格式： 输入在第1行中给出N和K（1≤K<N≤100），此后N行，每行包含一个长度不超过10的、仅由小写英文字母组成
在日常模型训练过程中，模型有多种选择，模型的参数同样也有多种选择，如何根据同一批数据选出最适合的模型和参数呢？ 一般情况下，模型还比较好选择，是选用机器学习中分类模型例如 LR、SVM或XGBoost等，还是使用深度学习模型CNN、LSTM等。但是参数的选择就让人很头疼，每个模型都有一堆参数，参数
Video Cutter Joiner请添加链接描述 has support for most of the popular formats; AVI, MPEG, MP4, WMV, 3GP and FLV. The application is easy to use and has a simple, standard interface. What is really noticeable about this application is the speed. Free Video Cutt
20. Dog,Man's Best Friend 狗,人类最好的朋友①The dogs has always been considered man's best friend.Always noted for being particularly faithful in watching over children,he also has his place by the fireside,in the crowd pasture,on the sheep rangr,and be
1012 The Best Rank （25 分） To evaluate the performance of our first year CS majored students, we consider their grades of three courses only: C- C Programming Language, M - Mathematics (Calculus or Linear Algrbra), and E - English. At the mean time, we
To evaluate the performance of our first year CS majored students, we consider their grades of three courses only: C - C Programming Language, M - Mathematics (Calculus or Linear Algrbra), and E - English. At the mean time, we encourage students b
使用激活码的方式激活idea；点击自动生成激活码. http://idea.lanyus.com/getkey?userName=lan+yu 该教程转自https://blog.csdn.net/best_luxi/article/details/81479820
全栈工程师开发手册 （作者：栾鹏） python数据挖掘系列教程 优化的相关的知识内容可以参考 https://blog.csdn.net/luanpeng825485697/article/details/78765923 网格搜索GridSearchCV GridSearchCV用于系统地遍历多种参数组合，通过交叉验证确定最佳效果参数。 classsklearn.m
Description Pizza has always been a staple on college campuses. After the downturn in the economy, it is more important than ever to get the best deal, namely the lowest cost per square inch. Consider, for example, the following menu for a store sellin
一、使用内置函数 def toLowerCase(self, str: 'str') -> 'str': return str.lower() 28ms，12.4M class Solution: def toLowerCase(self, str: 'str') -> 'str': res = '' for m in str:
CF1117A Best Subsegment 乍一看好像很难,仔细想一下发现就是弱智题... 任意一段平均数显然不会超过最大的数,若只取最大数即可达到平均数为最大数. 于是只用取最长的一段连续的最大数即可. #include<bits/stdc++.h> using namespace std; #define ll long long #define mp make_
