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  • 业务可视化-让你的流程图"Run"起来2022-07-01 21:36:56

    前言 最近在研究业务可视化的问题,在日常的工作中,流程图和代码往往是分开管理的。 一个被维护多次的系统,到最后流程图和代码是否匹配这个都很难说。 于是一直有一个想法,让程序直接读流程图,根据流程图的配置来决定程序运行的顺序。 一转眼三年过去了,目前这个想法已经逐步落地实现变

  • R语言中arrows函数2022-05-17 11:34:45

      1、 > plot(1:5, 1:5, xlim = c(0,6), ylim = c (0,6), type = "n") > arrows(x0 = 1, y0 = 1, x1 = 4, y1 = 4)     2、 同时画两个箭头 > plot(1:5, 1:5, xlim = c(0,6), ylim = c (0,6), type = "n") > arrows(x0 = c(1, 1), y0 = c(1, 2),

  • 【leetcode】452. Minimum Number of Arrows to Burst Balloons2022-01-14 09:32:53

    There are some spherical balloons taped onto a flat wall that represents the XY-plane. The balloons are represented as a 2D integer array points where points[i] = [xstart, xend] denotes a balloon whose horizontal diameter stretches between xstart and

  • ZOJ4127 Grid with Arrows(欧拉路径的判断)2020-10-07 20:33:48

    对于本题,本质上是哈密顿回路,但是由于特殊性,每个点仅有一条往外的连边 因此,本题等价于欧拉路径的判断,只需要根据欧拉路径判断答案即可 即连通性和出度入度间的关系 #include<bits/stdc++.h> using namespace std; typedef long long ll; typedef pair<int,int> pll; const int N=

  • 452. Minimum Number of Arrows to Burst Balloons2020-07-24 23:03:55

    package LeetCode_452 /** * 452. Minimum Number of Arrows to Burst Balloons * https://leetcode.com/problems/minimum-number-of-arrows-to-burst-balloons/description/ * * There are a number of spherical balloons spread in two-dimensional space. * For ea

  • LeetCode 452. Minimum Number of Arrows to Burst Balloons(用最少数量的箭引爆气球)2020-03-16 14:37:33

    题目描述:气球在一个水平数轴上摆放,可以重叠,飞镖垂直投向坐标轴,使得路径上的气球都被刺破。求解最小的投飞镖次数使所有气球都被刺破。 如果最多有 n 个不重叠的区间,那么就至少需要 n 个箭头穿透所有区间 箭头如果碰到气球的边界气球也会爆炸,所以说相当于区间的边界触碰也

  • LeetCode 452. Minimum Number of Arrows to Burst Balloons2019-12-19 12:03:49

    原题链接在这里:https://leetcode.com/problems/minimum-number-of-arrows-to-burst-balloons/ 题目: There are a number of spherical balloons spread in two-dimensional space. For each balloon, provided input is the start and end coordinates of the horizontal diameter

  • Minimum Number of Arrows to Burst Balloons2019-07-23 13:03:59

    There are a number of spherical balloons spread in two-dimensional space. For each balloon, provided input is the start and end coordinates of the horizontal diameter. Since it's horizontal, y-coordinates don't matter and hence the x-coordinates

  • Bootstrap4.0兼容tree方法2019-05-09 09:43:05

    bootstrap-treeview 是bootstrap的一个树形插件,他不可以在 bootstrap 高于 3.3.7 版本中使用。   那么,问题就来了,Bootstrap4.0中怎么办啦? 验证后发现,主要是Bootstrap4.0中将一些图标被去除了,设置一下就好 JS $('#tree').treeview({ data: html,

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