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  • print 高级用法2019-10-21 10:50:58

    my_name='zhangsan'print(f"Let's talk {my_name},Don't paly basketball in the room")#等价于下面方式print("Let's talk {},Don't paly basketball in the room".format(my_name))#打印结果如下:'''Let's talk z

  • (转)WebRTC信令控制与STUN/TURN服务器搭建2019-10-19 18:56:46

    转:https://rtcdeveloper.com/t/topic/13742 本文将向大家介绍两个方面的知识: WebRTC信令控制 STUN/TURN服务器的搭建 在前面的文章中已经向大家介绍了如何构建信令服务器。但构建的信令服务器是如何工作的?那些消息需要信令服务器控制和中转?这些此前并没有做详细的说明,而本文将对

  • CF Round #592 (Div. 2) 题解2019-10-14 21:58:20

    Problem - A Tomorrow is a difficult day for Polycarp: he has to attend \(a\) lectures and \(b\) practical classes at the university! Since Polycarp is a diligent student, he is going to attend all of them. While preparing for the university, Polycarp

  • mysql优化查询的方式2019-10-03 10:02:59

    优化查询的方式 一、假设有三张表 Room id 1 2 .. 1000 User: id 1 .. 10000 Booking: user_id room_id time_id date 1 1 8:00 2017-11-11 1 2

  • Exercise 34 - branches and functions2019-09-30 17:00:35

      from sys import exitdef gold_room(): print("This room is full of gold. How much do you take?") next = input("> ") if "0" in next or "1" in next: how_much = int(next) else: dead("

  • 【HDU5566】Clarke and room(AC自动机)(树链剖分)(线段树)2019-09-23 19:04:57

    传送门 题解: 在线也好离线也好,反正AC自动机只建在有询问的线段树节点上就行了。 由于树链剖分形态的特殊性,可能很多线段树节点上都没有询问(是两条链标号的并),建出来就是浪费时间。 代码: #include<bits/stdc++.h> #define ll long long #define re register #define gc get

  • Dudu's maze (DFS染色|并查集)2019-09-15 11:53:04

    To seek candies for Maomao, Dudu comes to a maze. There are nn rooms numbered from 11 to nn and mmundirected roads. There are two kinds of rooms in the maze -- candy room and monster room. There is one candy in each candy room, and candy room is safe.

  • Dudu's maze2019-09-14 23:55:37

     23.7%  1000ms  262144K   To seek candies for Maomao, Dudu comes to a maze. There are nn rooms numbered from 11 to nn and mm undirected roads. There are two kinds of rooms in the maze -- candy room and monster room. There is one candy in each c

  • 静态属性、类方法、静态方法2019-09-05 12:02:05

    静态属性、类方法、静态方法 1. 静态属性:在函数前加@property,将函数逻辑”封装“成数据属性,外部直接调用函数名,如同调用属性一样。这个函数是可以调用类和实例的属性的,    静态属性的作用是把类的方法隐藏起来(可以把背后的逻辑隐藏起来),让用户感觉是在调用属性,而不是方法; c

  • HihoCoder - 1828 Saving Tang Monk II(bfs+优先队列)2019-09-03 10:41:45

    《Journey to the West》(also 《Monkey》) is one of the Four Great Classical Novels of Chinese literature. It was written by Wu Cheng’en during the Ming Dynasty. In this novel, Monkey King Sun Wukong, pig Zhu Bajie and Sha Wujing, escorted Tang Monk to

  • swoole实现多对多群聊(一)2019-08-29 19:07:57

    参考博客,大家可以去看看原文,这里只是根据业务需求做了更改 后端参考 swoole创建多人多房间聊天室一 swoole创建多人多房间聊天室二 swoole创建多人多房间聊天室三 前端参考 微信小程序开发聊天室 搭建环境和域名配置这里就先跳过了,大家可以自行百度 话不多说直接上代码 P

  • 【CodeForce】A. Hotelier(思维)2019-08-12 10:38:13

    Amugae has a hotel consisting of 10 rooms. The rooms are numbered from 0 to 9 from left to right. The hotel has two entrances — one from the left end, and another from the right end. When a customer arrives to the hotel through the left entrance, they

  • Android 使用Room 生成不了数据库文件2019-08-06 20:39:11

    异常如下 java.lang.RuntimeException: cannot find implementation for com.snowman.myapplication.UserDatabase. UserDatabase_Impl does not exist com.snowman.myapplication.UserDatabase. UserDatabase_Impl does not exist 经过查询应该是一项依赖没加 kapt "an

  • LeetCode 841. Keys and Rooms2019-08-04 09:01:18

    原题链接在这里:https://leetcode.com/problems/keys-and-rooms/ 题目: There are N rooms and you start in room 0.  Each room has a distinct number in 0, 1, 2, ..., N-1, and each room may have some keys to access the next room.  Formally, each room i has a l

  • Codeforces B. Mouse Hunt(强连通分解缩点)2019-08-03 19:52:28

    题目描述: Mouse Hunt time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Medicine faculty of Berland State University has just finished their admission campaign. As usual, about 80%of applicants are gi

  • Save the Room【找规律】2019-08-03 11:05:57

    Save the Room 时间限制: 1 Sec 内存限制: 128 MB 提交: 149 解决: 90 [提交] [状态] [命题人:admin] 题目描述 Bob is a sorcerer. He lives in a cuboid room which has a length of A, a width of B and a height of C, so we represent it as ABC. One day, he finds

  • linux下以CSV格式向Cassandra数据库导入数据2019-07-28 16:42:02

    1.文件准备:首先我们可以在excel里建一个表格,然后把它另存为转换成csv格式,用winscp将csv文件传到Linux系统中去,本文以room.csv为例。 2.启动cqlsh:进入Cassandra的目录下,输入Cassandra -f启动Cassandra,此时可能会出现一直启动的状态,但这并不影响我们接下来的操作,我们可以再打

  • ESP8266乐鑫版本的(支持云端升级 (Boot 模式)烧写方法,(V1.5.4官方介绍如下)(BOOT模式)2019-07-27 20:57:29

    硬件平台: nodeMCU devkit核心板,带ch340g,应该是仿造的,官方是cp2102驱动,安信可科技有连接https://wiki.ai-thinker.com/esp8266/boards/nodemcu 编译环境:安装安信可一体化开发环境  AiThinker_IDE.exe 是安信可科技为方便广大用户而推出的基于 Windows + Cygwin + Eclipse + GCC

  • Java8的Stream API使用2019-07-27 11:01:00

    前言 这次想介绍一下Java Stream的API使用,最近在做一个新的项目,然后终于可以从老项目的祖传代码坑里跳出来了。项目用公司自己的框架搭建完成后,我就想着把JDK版本也升级一下吧(之前的项目,最高就能用JDK7),但是后来发现公司的项目部署打包平台最高只支持到JDK8。那好吧,既然就支持到JDK8

  • Codeforces 1180E Serge and Dining Room2019-06-26 15:50:06

    题意: 有\(n\)个菜肴,有\(m\)个小朋友,每个菜肴的价格为\(a_i\),每个小朋友有\(b_i\)元钱,小朋友从\(1 \rightarrow m\)依次购买菜肴,当第\(i\)个小朋友轮到的时候,他会购买他买的起的最贵的,否则就离开。 要求支持修改第\(i\)个菜肴的价格和修改第\(i\)个小朋友的拥有的钱数的两种操作,每次

  • A. Chat room2019-06-10 11:49:40

    A. Chat room time limit per test1 second memory limit per test256 megabytes inputstandard input outputstandard output Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybod

  • egg-socket在egg中的使用2019-05-30 13:48:16

     config/config.default.js exports.io = { init: {}, namespace: { '/': { //对应router.js里的 of('/') connectionMiddleware: [ 'auth' ], //对应io/middleware/auth packetMiddleware: [ 'filter

  • django channels2019-05-08 16:53:04

    参考文档:https://channels.readthedocs.io/en/latest/index.html pip3 install djangopip3 install channels 安装django及channels 创建channels库根路由配置文件,根路由配置文件类似Django URLconf,它会告诉Channels当收到由Channes服务器发过来的Http请求时,应该执行什么代码: #

  • hdu_1050 Moving Tables 贪心2019-05-01 08:48:24

    Moving Tables Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 45555    Accepted Submission(s): 14817   Problem Description The famous ACM (Advanced Computer Maker) Company has rented a floor of

  • 15 Django REST Framework 添加自定义搜索条件2019-04-26 17:38:19

    一、ListModelMixin源码 # 源码class ListModelMixin(object): """ List a queryset. """ def list(self, request, *args, **kwargs): queryset = self.filter_queryset(self.get_queryset()) page = self.paginate_quer

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