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  • 1136 A Delayed Palindrome2020-03-15 09:01:04

     由于给出的数可能超出 long long范围,所以不能对两数直接求和,必须模拟加法运算过程,不然最后一个测试点无法通过。 中文版。 1079 延迟的回文数 1 #include<iostream> 2 #include<algorithm> 3 using namespace std; 4 5 bool isPalindrome(string str) { 6 for(int i

  • B - Yet Another Palindrome Problem2020-03-14 23:00:35

    You are given an array aa consisting of nn integers. Your task is to determine if aa has some subsequence of length at least 33 that is a palindrome. Recall that an array bb is called a subsequence of the array aa if bb can be obtained by r

  • [codeforces 1324B] Yet Another Palindrome Problem 回文+边界处理2020-03-13 10:43:23

    Codeforces Round #627 (Div. 3)   比赛人数6434 [codeforces 1324B]  Yet Another Palindrome Problem   回文+边界处理 总目录详见https://blog.csdn.net/mrcrack/article/details/103564004 也在线测评地址http://codeforces.com/contest/1324/problem/B Problem Lang

  • 125. Valid Palindrome - two pointers2020-03-11 18:01:45

    125. Valid Palindrome Easy Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases. Note: For the purpose of this problem, we define empty string as valid palindrome. Example 1: Input: "A man, a p

  • Codeforces Round #620 (Div. 2) Longest Palindrome2020-02-21 11:40:20

    解题报告: 思路:找出和它串构成回文的串,找出本身是回文的串。 模拟过程: 4 2 oo ox xo xx 和它串构成回文的串:ox xo 本身是回文的串:oo xx(只需要一个,因为串之间不相等) 答案:oxooxo 长度为6。 代码: #include<bits/stdc++.h> using namespace std; typedef long long ll; const ll

  • 5. Longest Palindromic Substring**2020-02-20 10:38:36

    5. Longest Palindromic Substring** https://leetcode.com/problems/longest-palindromic-substring/ 题目描述 Given a string s, find the longest palindromic substring in s. You may assume that the maximum length of s is 1000. Example 1: Input: "babad" Ou

  • Leetcode 9. Palindrome Number2020-02-06 19:01:41

    Determine whether an integer is a palindrome. An integer is a palindrome when it reads the same backward as forward. Example 1: Input: 121Output: trueExample 2: Input: -121Output: falseExplanation: From left to right, it reads -121. From right to left, it

  • UVa 11475 - Extend to Palindrome2020-02-06 17:53:51

    Contents Problem題目網址 在後面接上最少的字元,使得原來的字串為回文。 Solution利用原字串和其反轉字串,做 KMP 加速配對過程,找出原字串和反轉後的匹配可以配對到哪,輸出原字串後,再將無法配對完成的反轉字串輸出。 原字串 S: xyzxyz 反轉 R: zyxzyx 只能完成一個配對 S[5]

  • LintCode 223: Palindrome Linked List2020-02-04 14:44:45

    Palindrome Linked List Implement a function to check if a linked list is a palindrome. Example Example 1: Input: 1->2->1 output: true Example 2: Input: 2->2->1 output: false Challenge Could you do it in O(n) time and O(1) space? 解法1: 我用的stack

  • 336. Palindrome Pairs2020-02-04 09:03:33

    Given a list of unique words, find all pairs of distinct indices (i, j) in the given list, so that the concatenation of the two words, i.e. words[i] + words[j] is a palindrome. Example 1: Input: ["abcd","dcba","lls","s&

  • Palindrome2020-02-02 18:57:15

    A palindrome is a symmetrical string, that is, a string read identically from left to right as well as from right to left. You are to write a program which, given a string, determines the minimal number of characters to be inserted into the string in orde

  • 【Manacher Algorithm】POJ 3974 Palindrome(模板)2020-02-01 16:42:07

     POJ 3974 Palindrome 求字符串最长回文的长度。 因为时间限制,所以考虑时间复杂度为O(n)的Manacher算法。 Manacher详解+例题 #include <iostream> #include <cstdio> #include <cmath> #include <string> #include <cstring> #include <algorithm> #include <limits>

  • leetcode#9Palindrome Number2020-02-01 09:37:40

    Determine whether an integer is a palindrome. An integer is a palindrome when it reads the same backward as forward. Example 1: Input: 121 Output: true Example 2: Input: -121 Output: false Explanation: From left to right, it reads -121. From right to le

  • Codeforces Round #507 (Div. 2, based on Olympiad of Metropolises)2020-01-31 16:51:18

    题目链接:https://codeforces.com/contest/1040 A - Palindrome Dance int x[1005]; void test_case() { int n, a, b; scanf("%d%d%d", &n, &a, &b); for(int i = 1; i <= n; ++i) scanf("%d", &x[i]); int sum

  • 6-10 判断回文字符串 (20分)2020-01-30 10:07:17

    本题要求编写函数,判断给定的一串字符是否为“回文”。所谓“回文”是指顺读和倒读都一样的字符串。如“XYZYX”和“xyzzyx”都是回文。 函数接口定义: bool palindrome( char *s ); 函数palindrome判断输入字符串char *s是否为回文。若是则返回true,否则返回false。 裁判测试

  • 二、破坏回文串(Biweekly18)2020-01-28 20:37:38

    题目描述: 给你一个回文字符串 palindrome ,请你将其中 一个 字符用任意小写英文字母替换,使得结果字符串的字典序最小,且 不是 回文串。 请你返回结果字符串。如果无法做到,则返回一个空串。 示例 1: 输入:palindrome = “abccba” 输出:“aaccba” 示例 2: 输入:palindrome = “a”

  • 回文序列2020-01-27 17:41:31

    A palindrome is a symmetrical string, that is, a string read the same from left to right as from right to left. You are asked to write a program which, given a string, determines whether it is a palindrome or not. Input The first line contain a single i

  • LeetCode 9. Palindrome Number2020-01-27 09:43:05

    LeetCode 9. Palindrome Number 9.Palindrome Number Determine whether an integer is a palindrome. An integer is a palindrome when it reads the same backward as forward. Example 1: Input: 121 Output: true Example 2: Input: -121 Output: false Explanation:

  • LeetCode 234. Palindrome Linked List2020-01-21 12:00:51

    Description Given a singly linked list, determine if it is a palindrome. Example 1: Input: 1->2 Output: false Example 2: Input: 1->2->2->1 Output: true Follow up: Could you do it in O(n) time and O(1) space? Solution 要求时间复杂度为O(n),空间复杂度为O(1)

  • 算法竞赛入门经典——数组和字符串2020-01-16 19:09:53

    算法竞赛入门经典——数组和字符串 注意点: 1.比较大的数组应尽量声明在main函数外,否则程序可能无法运行。 2.C语言的数组并不是“一等公民”,而是“受歧视”的。例如,数组不能够进行赋值操作,如果声明“int a[maxn],b[maxn]”,是不能赋值b=a的。如果要从数组a复制k个元素到数组b

  • 寒假练习——Palindromes2020-01-15 20:03:57

    A regular palindrome is a string of numbers or letters that is the same forward as backward. For example, the string "ABCDEDCBA" is a palindrome because it is the same when the string is read from left to right as when the string is read from ri

  • 习题8-8 判断回文字符串2020-01-14 19:57:34

    https://pintia.cn/problem-sets/12/problems/342   1 bool palindrome(char *s) 2 { 3 int n, i, k; 4 bool ret; 5 6 n = strlen(s); 7 i = 0; 8 k = n - 1; 9 while (i <= k) 10 { 11 if (s[i] != s[k]) 12 { 1

  • 动态规划-Minimum Insertion Steps to Make a String Palindrome2020-01-05 12:01:19

    2020-01-05 11:52:40 问题描述: 问题求解: 好像多次碰到类似的lcs的变种题了,都是套上了回文的壳。这里再次记录一下。 其实本质就是裸的lcs,就出结果了。 public int minInsertions(String s) { StringBuffer sb = new StringBuffer(s); String b = sb.reverse(

  • String 字符串2020-01-02 12:06:22

    题号 题目链接 说明 基础 28 Implement strStr() 14 Longest Common Prefix 58 Length of Last Word 387 First Unique Character in a String 383 Ransom Note 344 Reverse String 151 Reverse Words in a String 186 Reverse Words in a String II 345 Reverse Vowels of a Str

  • @codeforces - 932G@ Palindrome Partition2019-12-11 19:01:39

    目录 @description@ @solution@ @accepted code@ @details@ @description@ 给定一个字符串 s,求有多少种方案可将其划分成偶数个段 \(p_1, p_2, ..., p_k\),使得 \(p_i = p_{k-i+1}\)。 模 10^9 + 7。 2 ≤ |s| ≤ 10^6。 原题戳这里。 @solution@ 回文划分有一个经典的

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