# dfs的遍历 class Solution: def generateParenthesis(self, n: int) -> List[str]: if n <= 0: return [] # 特例判断 res = [] #设置返回列表 def dfs(paths, left, right): #构造dfs函数进行遍历 if left > n or right > left or r
专注分享技术,共同学习,共同进步。侵权联系[81616952@qq.com]
Copyright (C)ICode9.com, All Rights Reserved.
ICode9版权所有