1.语法 WITH cte_name ( column_name [,...n] ) AS ( --定点成员（锚成员） SELECT column_name [,...n] FROM tablename WHERE conditions UNION ALL --递归成员 SELECT column_name [,...n] FROM cte_name INNER JOIN CTE ON conditions ) -- St
Employee 表包含所有员工，他们的经理也属于员工。每个员工都有一个 Id，此外还有一列对应员工的经理的 Id。 +----+-------+--------+-----------+| Id | Name | Salary | ManagerId |+----+-------+--------+-----------+| 1 | Joe | 70000 | 3 || 2 | Henry | 80000
第二天3.数据库：超过经理收入的员工+----+-------+--------+-----------+| Id | Name | Salary | ManagerId |+----+-------+--------+-----------+| 1 | Joe | 70000 | 3 || 2 | Henry | 80000 | 4 || 3 | Sam | 60000 | NULL || 4 | Max | 90
需求：Employee 表，请编写一个SQL查询来查找至少有5名直接下属的经理。 展示效果： Name John 1 Create table If Not Exists Employee (Id int, Name varchar(255), Department varchar(255), ManagerId int); 2 3 insert into Employee (Id, Name, Department, ManagerI
需求：Employee 表包含所有员工，他们的经理也属于员工。每个员工都有一个 Id，此外还有一列对应员工的经理的 Id。 数据样式： IdNameSalaryManagerId 1 Joe 70000 3 2 Henry 80000 4 3 Sam 60000 null 4 Max 90000 null 展示效果： Employee Joe 1 create table If
SQL架构 Employee 表包含所有员工，他们的经理也属于员工。每个员工都有一个 Id，此外还有一列对应员工的经理的 Id。 +----+-------+--------+-----------+ | Id | Name | Salary | ManagerId | +----+-------+--------+-----------+ | 1 | Joe | 70000 | 3 | | 2 | He
Employee表包含所有员工，包括他们的经理。每个员工都有一个 Id，此外还有一列对应的经理Id。 创建表和数据： drop table EmployeeCreate table If Not Exists Employee (Id int, Name varchar(255), Salary int, ManagerId int);Truncate table Employee;insert into Employee (Id,
Employee表包含所有员工，他们的经理也属于员工。每个员工都有一个 Id，此外还有一列对应员工的经理的 Id。 +----+-------+--------+-----------+ | Id | Name | Salary | ManagerId | +----+-------+--------+-----------+ | 1 | Joe | 70000 | 3 | | 2 | Henry | 8000
题目描述： The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id. +----+-------+--------+-----------+ | Id | Name | Salary | ManagerId | +----+-------+--------+-----------+
