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  • 【leetcode】452. Minimum Number of Arrows to Burst Balloons2022-01-14 09:32:53

    There are some spherical balloons taped onto a flat wall that represents the XY-plane. The balloons are represented as a 2D integer array points where points[i] = [xstart, xend] denotes a balloon whose horizontal diameter stretches between xstart and

  • [LeetCode] 1189. Maximum Number of Balloons2021-09-15 02:05:08

    Given a string text, you want to use the characters of text to form as many instances of the word "balloon" as possible. You can use each character in text at most once. Return the maximum number of instances that can be formed. Example 1: Inpu

  • 452. Minimum Number of Arrows to Burst Balloons2020-07-24 23:03:55

    package LeetCode_452 /** * 452. Minimum Number of Arrows to Burst Balloons * https://leetcode.com/problems/minimum-number-of-arrows-to-burst-balloons/description/ * * There are a number of spherical balloons spread in two-dimensional space. * For ea

  • Cupboard and Balloons CodeForces - 342C2020-03-25 16:59:10

    Cupboard and Balloons  CodeForces - 342C  找到不变的点 抓住不确定的点进行讨论 #include<iostream> #include<cmath> using namespace std; int main() { double r,h; cin>>r>>h; int ans; ans=2*int(h/r); double s=h-int(h/r)*r; if(s&

  • Leetcode 312. Burst Balloons2020-02-01 14:53:03

    题目链接     Code: 1 class Solution { 2 public: 3 int maxCoins(vector<int>& nums) { 4 vector<int> arr; 5 arr.push_back(1); 6 for(int i:nums){ 7 arr.push_back(i); 8 } 9 arr.push

  • LeetCode 452. Minimum Number of Arrows to Burst Balloons2019-12-19 12:03:49

    原题链接在这里:https://leetcode.com/problems/minimum-number-of-arrows-to-burst-balloons/ 题目: There are a number of spherical balloons spread in two-dimensional space. For each balloon, provided input is the start and end coordinates of the horizontal diameter

  • leetcode 312. Burst Balloons2019-09-09 17:53:21

    Given n balloons, indexed from 0 to n-1. Each balloon is painted with a number on it represented by array nums. You are asked to burst all the balloons. If the you burst balloon iyou will get nums[left] * nums[i] * nums[right] coins. Here left and

  • 牛客10 Popping Balloons2019-08-18 14:00:41

      题意:  平面上有n个点    用三条平行于x轴的线  和三条平行于y轴的线  (且相邻线间隔为r )  问 最多能覆盖多少点     每个点往下 和往左 设置两个“虚点”  题目就简化为一条横线一条竖线   oN  即可解决 #include<bits/stdc++.h>using namespace std;#define rep(

  • Minimum Number of Arrows to Burst Balloons2019-07-23 13:03:59

    There are a number of spherical balloons spread in two-dimensional space. For each balloon, provided input is the start and end coordinates of the horizontal diameter. Since it's horizontal, y-coordinates don't matter and hence the x-coordinates

  • 洛谷#CF342C#Cupboard and Balloons2019-07-13 12:02:19

    更好的阅读体验 来我的博客观看 Cupboard and Balloons 给定r和h,有一个立体图形 下部为宽r,长2r,高h的矩形 上部为宽r,正面为半径为r的半圆的立体图形 具体就看下面的图啦 解法 如图,我们可以看到,一种情况是下面都两个两个填,最上面能填两个 还有一种是下面填不到两个,只能上面填一个 最

  • leetcode 312. Burst Balloons2019-06-02 12:49:29

    312. Burst Balloons https://www.cnblogs.com/grandyang/p/5006441.html dp[i][j]表示打爆区间 [i,j] 中的所有气球能得到的最多金币。 计算的顺序是按照区间长度递增的顺序进行计算,从i-j长度为1到i-j长度为n。   class Solution {public: int maxCoins(vector<int>& nums) {

  • 打气球游戏——Burst Balloons2019-03-11 15:54:17

      有n个气球,编号为0到n-1,每个气球都有一个分数,存在nums数组中。每次吹气球i可以得到的分数为 nums[left] * nums[i] * nums[right],left和right分别表示i气球相邻的两个气球。当i气球被吹爆后,其左右两气球即为相邻。要求吹爆所有气球,得到最多的分数。    1 class Solution:

  • UVA-12627 Erratic Expansion2019-02-16 17:44:19

    题目链接 https://vjudge.net/problem/UVA-12627 题面 Description Piotr found a magical box in heaven. Its magic power is that if you place any red balloon inside it then, after one hour, it will multiply to form 3 red and 1 blue colored balloons. Then in the nex

  • ZOJ1003 Crashing Balloon【水题】2019-02-08 08:49:00

    Crashing Balloon Time Limit: 2 Seconds Memory Limit: 65536 KB On every June 1st, the Children's Day, there will be a game named "crashing balloon" on TV. The rule is very simple. On the ground there are 100 labeled balloons, with the number

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