标签：练习题 startswith 答案 以及 aric li 66 print alec
一、元素分类：
有如下值集合 [11,22,33,44,55,66,77,88,99,90...]，将所有大于 66 的值保存至字典的第一个key中，将小于 66 的值保存至第二个key的值中。
即： {'k1': 大于66的所有值, 'k2': 小于66的所有值}
li = [11,22,33,44,55,66,77,88,99,90] a = [] b = [] for k in li: if k>66: a.append(k) else: b.append(k) k1 = {'大于66的所有值':a} k2 = {'小于66的所有值':b} print(k1,k2)%注意输出时要对齐
---{'大于66的所有值': [77, 88, 99, 90]} {'小于66的所有值': [11, 22, 33, 44, 55, 66]}
二、查找
查找列表中元素，移除每个元素的空格，并查找以 a或A开头 并且以 c 结尾的所有元素。
li = ["alec", " aric", "Alex", "Tony", "rain"]
tu = ("alec", " aric", "Alex", "Tony", "rain")
dic = {'k1': "alex", 'k2': ' aric', "k3": "Alex", "k4": "Tony"}
li = ["alec", " aric", "Alex", "Tony", "rain"] for i in li: v = i.strip() if (v.startswith("a") or v.startswith("A") and v.endswith("c")): print(v) ---alec aric tu = ("alec", " aric", "Alex", "Tony", "rain") for n in tu: v = n.strip() if (v.startswith("a") or v.startswith("A") and v.endswith("c")): print(v) ---alec aric dic = {'k1': "alex", 'k2': ' aric', "k3": "Alex", "k4": "Tony"} for i in dic.values(): v = i.strip() if (v.startswith("a") or v.startswith("A") and v.endswith("c")): print(v) ----alex aric
三、输出商品列表，用户输入序号，显示用户选中的商品
商品 li = ["手机", "电脑", '鼠标垫', '游艇']
n = input("请输入序号：") li = ["手机", "电脑", '鼠标垫', '游艇'] for i ,a1 in enumerate(li,1): print(i,a1) b1 = int(n) print(li[b1 - 1])
四、购物车
功能要求：
要求用户输入总资产，例如：2000
显示商品列表，让用户根据序号选择商品，加入购物车
购买，如果商品总额大于总资产，提示账户余额不足，否则，购买成功。
附加：可充值、某商品移除购物车
goods = [ {"name": "电脑", "price": 3000}, {"name": "鼠标", "price": 103}, {"name": "游艇", "price": 200000}, {"name": "美女", "price": 998}, ] total = 0 pay = 0 shopping = {}#建立商品字典（keys商品、values数量） zongji = input("请输入总资产") if zongji.isdigit(): total = str(zongji) print("总资产为：" + total + "元") else: print("请输入数字！") while True: caozuo = input("请输入操作：1.显示商品，2.充值，3.退出") caozuo = int(caozuo) if int(caozuo) == 1: for g in enumerate(goods,1): print(g[0],":",g[1]["name"],g[1]["price"],"元") while True: buy_good = input("请依次输入购买商品编号(结账输入g，移除商品输入d)") if buy_good.isdigit(): buy = int(buy_good) if buy >0 and buy <= len(goods): if goods[buy-1]["name"] in shopping.keys():#.has_key(k)是否存在 shopping[goods[buy-1]["name"]] = int(shopping[goods[buy-1]["name"]])+1 pay += int(goods[buy-1]["price"]) print("已选购:") for keys, values in shopping.items(): print(str(keys), "数量为", str(values)) else: shopping.setdefault(goods[buy-1]["name"],1) #setdefault添加 pay += int(goods[buy - 1]["price"]) print("已选购:") for keys,values in shopping.items(): print(str(keys),"数量为",str(values)) elif buy_good == "g": if int(pay) <= int(total): print("购买成功，共计消费"+str(pay)+"元，余额为"+str(int(total)-int(pay))+"元") break else: print("共消费"+str(pay)+"元，总资产为"+str(total)+"元，欠"+str(int(pay)-int(total))+"元，请充值！") chongzhi = input("请输入充值金额") if chongzhi.isdigit(): total = int(total) + int(chongzhi) print("充值成功，总资产为：" + str(total) + "元。") # 字符串+数字 会报错 else: print("请输入数字！") elif buy_good == "d": print("已选购:") for keys, values in shopping.items(): print(str(keys), "数量为", str(values)) del_good = input("请输入移除商品编号") if del_good.isdigit() and int(del_good) > 0 and int(del_good) <= len(goods): del_good = int(del_good) if goods[int(del_good) - 1]["name"] in shopping.keys(): # .has_key(k)是否存在 if int(shopping[goods[del_good-1]["name"]]) == 1: shopping.pop(goods[del_good-1]["name"]) print("移除成功，已选购:") for keys, values in shopping.items(): print(str(keys), "数量为", str(values)) else: shopping[goods[del_good - 1]["name"]] = int(shopping[goods[del_good - 1]["name"]]) - 1 pay -= int(goods[del_good - 1]["price"]) print("已选购:") for keys, values in shopping.items(): print(str(keys), "数量为", str(values)) else: print("无此商品！") else: print("输入错误！") else: print("输入错误！") break elif int(caozuo) == 2: chongzhi = input("请输入充值金额") if chongzhi.isdigit(): print("充值成功，总资产为：" + str(int(total)+int(chongzhi)) + "元。")#字符串+数字 会报错 else: print("请输入数字！") elif int(caozuo) == 3: print("退出操作！") break else: print("输入错误！")
标签：练习题,startswith,答案,以及,aric,li,66,print,alec 来源： https://www.cnblogs.com/zhoujie228/p/13965194.html
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