标签:Sort nums two Wiggle num swap 280
package LeetCode_280 /** * 280. Wiggle Sort * (locked by leetcode) * https://www.lintcode.com/problem/wiggle-sort/description * * Given an unsorted array nums, reorder it in-place such that nums[0] <= nums[1] >= nums[2] <= nums[3].... Example: Input: nums = [3,5,2,1,6,4] Output: One possible answer is [3,5,1,6,2,4] Please complete the problem in-place. * */ class Solution { fun wiggleSort(nums: IntArray) { for (i in 1 until nums.size) { //follow by this situation: nums[0] <= nums[1] >= nums[2] <= nums[3] //so if i is even and and nums[i] > nums[i-1], swap this two num and //if if i is odd and nums[i] < nums[i-1], swap this two num also if (i % 2 == 0 && nums[i] > nums[i - 1] || i % 2 != 0 && nums[i] < nums[i - 1]) { swap(nums, i, i - 1) } } } private fun swap(nums: IntArray, i: Int, j: Int) { val temp = nums[i] nums[i] = nums[j] nums[j] = temp } }
标签:Sort,nums,two,Wiggle,num,swap,280 来源: https://www.cnblogs.com/johnnyzhao/p/13110665.html
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