ICode9

精准搜索请尝试: 精确搜索
首页 > 其他分享> 文章详细

CIS 413/513 Advanced Data Structures

2020-01-31 19:03:00  阅读:326  来源: 互联网

标签:operations index data 413 CIS time NextWhite Data constraints


CIS 413/513 Advanced Data Structures
Winter 2020
Assignment 2
due Monday, February 3, 2020
1. (from DPV) Here’s a problem that occurs in automatic program analysis. For a set of
variables x1, x2, . . . , xn you are given some equality constraints of the form “xi = xj” and
some disequality constraints of the form “xi = xj”. Is it possible to satisfy all of them?
For example, the constraints
x1 = x2, x2 = x3, x3 = x4, x1 = x4
cannot be satisfied. Give an algorithm that takes as input m constraints over n variables and
decides whether the constraints can be satisfied.
2. (from Er) Suppose we want to maintain an array X[1 . . . n] of bits, which are all initially zero,
subject to the following operations.
• Lookup(i): Given an index i, return X[i].
• Blacken(i): Given an index i < n, set X[i] ← 1.
• NextWhite(i): Given an index i, return the smallest index ji such that X[j] = 0.
(Because we never change X[n], such an index always exists.)
If we use the array X[1 . . . n] itself as the only data structure, it is trivial to implement
Lookup andBlacken in O(1) time and NextWhite in O(n) time. But you can do better!
Describe data structures that support Lookup in O(1) worst-case time and the other two
代写CIS 413/513 数据结构作业operations in the following time bounds. (We want a different data structure for each set of
time bounds, not one data structure that satisfies all bounds simultaneously!)
(a) The worst-case time for both Blacken and NextWhite is O(log n).
(d) The worst-case time for Blacken is O(1), and the amortized time for NextWhite is
O(α(n)).
(Hints)
• (a) think of a self-balancing search tree
• (a) you may need the Successor function
• (d) α(n) can be replaced by lg∗ n • (d) the amortized bound did not depend on the Union function being done by-rank
• (d) there is no Whiten.
3. (from Er) Consider the following simpler alternative to splaying:
MoveToRoot(v):
while parent(v) != null
single rotate at v
1
Prove that the amortized cost of MoveToRoot in an n-node binary tree can be Ω(n). That
is, prove that for any integer k, there is a sequence of k MoveToRoot operations that
require Ω(kn) time to execute
4. (for 551 students) exercise 5 from http://jeffe.cs.illinois.edu/teaching/algorithms/notes/10-
scapegoat-splay.pdf
如有需要,请加QQ:99515681 或邮箱:99515681@qq.com 微信:codehelp

标签:operations,index,data,413,CIS,time,NextWhite,Data,constraints
来源: https://www.cnblogs.com/okniyjava/p/12245673.html

本站声明: 1. iCode9 技术分享网(下文简称本站)提供的所有内容,仅供技术学习、探讨和分享;
2. 关于本站的所有留言、评论、转载及引用,纯属内容发起人的个人观点,与本站观点和立场无关;
3. 关于本站的所有言论和文字,纯属内容发起人的个人观点,与本站观点和立场无关;
4. 本站文章均是网友提供,不完全保证技术分享内容的完整性、准确性、时效性、风险性和版权归属;如您发现该文章侵犯了您的权益,可联系我们第一时间进行删除;
5. 本站为非盈利性的个人网站,所有内容不会用来进行牟利,也不会利用任何形式的广告来间接获益,纯粹是为了广大技术爱好者提供技术内容和技术思想的分享性交流网站。

专注分享技术,共同学习,共同进步。侵权联系[81616952@qq.com]

Copyright (C)ICode9.com, All Rights Reserved.

ICode9版权所有