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单向链表

2019-08-06 21:57:48  阅读:151  来源: 互联网

标签:tmp head int 单向 next 链表 IntSSLNode tail


链表节点(其中info 表示节点信息,next是下一个节点引用,其中info可以通过template<class T> 实现泛型链表)

#pragma once
class IntSSLNode
{
public:
    IntSSLNode()
    {
        next = 0;
        info = 0;
    }
    IntSSLNode(int info, IntSSLNode* in = 0)
    {
        this->info = info;
        next = in;
    }
    int info;
    IntSSLNode* next;
};

链表类

#pragma once
#include "IntSSLNode.h"
class IntSSList
{
public:
    IntSSList()
    {
        head = tail = 0;
    }
    ~IntSSList();
    int isEmpty()
    {
        return head == 0;
    }
    void addToHead(int);
    void addTotail(int);
    int deleteFromHead();
    int deleteFromTail();
    void deleteNode(int);
    bool isInList(int) const;
    
private:
    IntSSLNode* head, * tail;
};
#include<iostream>
#include "IntSSList.h"

IntSSList::~IntSSList() {
    for (IntSSLNode* p; !isEmpty();)
    {
        p = head->next;
        delete head;
        head = p;
    }
}

void IntSSList::addToHead(int el)
{
    head = new IntSSLNode(el, head);

    if (tail == 0)
    {
        tail = head;
    }
}

void IntSSList::addTotail(int el)
{
    if (tail != 0)
    {
        tail->next = new IntSSLNode(el);
        tail = tail->next;
    }
    else
    {
        head = tail = new IntSSLNode(el);
    }
}

int IntSSList::deleteFromHead()
{
    int el = head->info;
    IntSSLNode* temp = head;
    if (head == tail)
    {
        head = tail = 0;
    }
    else
    {
        head = head->next;
    }
    delete temp;

    return el;
}

int IntSSList::deleteFromTail()
{
    int el = tail->info;

    if (head == tail)
    {
        delete head;
        head = tail = 0;
    }
    else
    {
        IntSSLNode* tmp;

        for (tmp = head; tmp->next != tail; tmp = tmp->next);

        delete tail;
        tail = tmp;
        tail->next = 0;

    }
    return el;
}

void IntSSList::deleteNode(int el)
{
    if (head != 0)

        if (head == tail && el == head->info) {
            delete head;
            head = tail = 0;

        }
        else if (el == head->info)
        {
            IntSSLNode* tmp = head;
            head = head->next;
            delete tmp;
        }
        else
        {
            IntSSLNode* pred,* tmp;

            for (pred=head,tmp=head->next;
                 tmp!=0 && !(tmp->info == el);
                 pred=pred->next,tmp=tmp->next);

            if (tmp != 0)
            {
                pred->next=tmp->next; //三个节点删除中间一个节点,需要把上一个节点和下一个节点链接起来。
                
                if (tmp == tail)  //当删除的节点是末端节点则新的末端节点是上一个节点
                {
                    tail = pred;
                }
                
                delete tmp;
            }
        }
}
bool IntSSList::isInList(int el) const{
    IntSSLNode* tmp;
    
    for (tmp = head; tmp != 0 && !(tmp->info == el); tmp = tmp->next);

    return tmp != 0;
}

测试

int main()
{
    IntSSList* list = new IntSSList();

    list->addTotail(1);
    list->addTotail(2);
    list->addTotail(3);
    list->addTotail(4);
    list->addToHead(5);

    //int i = list->deleteFromHead();

    //i = list->deleteFromTail();

    list->deleteNode(3);

}

 

标签:tmp,head,int,单向,next,链表,IntSSLNode,tail
来源: https://www.cnblogs.com/ms_senda/p/11312093.html

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