标签:people int greedy limit boats Input boat
881. Boats to Save People MediumYou are given an array people
where people[i]
is the weight of the ith
person, and an infinite number of boats where each boat can carry a maximum weight of limit
. Each boat carries at most two people at the same time, provided the sum of the weight of those people is at most limit
.
Return the minimum number of boats to carry every given person.
Example 1:
Input: people = [1,2], limit = 3 Output: 1 Explanation: 1 boat (1, 2)
Example 2:
Input: people = [3,2,2,1], limit = 3 Output: 3 Explanation: 3 boats (1, 2), (2) and (3)
Example 3:
Input: people = [3,5,3,4], limit = 5 Output: 4 Explanation: 4 boats (3), (3), (4), (5)
Constraints:
1 <= people.length <= 5 * 104
1 <= people[i] <= limit <= 3 * 104
为什么可以使用最大匹配最小?
因为一只船最多只能容纳两个人,所以我们可以从最重的船开始放,那么为什么要匹配最轻的船?因为如果最轻的都匹配不了的话
class Solution { public int numRescueBoats(int[] people, int limit) { Arrays.sort(people); int left = 0,right = people.length-1; int result = 0; while(left<=right){ if(people[right]+people[left]<=limit){ left++;right--; } else{ right--; } result++; } return result; } }
标签:people,int,greedy,limit,boats,Input,boat 来源: https://www.cnblogs.com/cynrjy/p/16414943.html
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