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实验5 结构体和文件

2022-06-07 00:01:43  阅读:147  来源: 互联网

标签:fp 文件 int char define Book 实验 include 结构


一、实验结论

task1

task1-1

#include <stdio.h>
#define N 5
#define M 80

typedef struct
{
	char name[M];
	char author[M];
}Book;

int main()
{
	Book x[N] = {	{"一九八四", "乔治.奥威尔"},
			{"美丽新世界", "赫胥黎"},
			{"昨日的世界", "斯蒂芬.茨威格"},
			{"万历十五年", "黄仁宇"},
			{"一只特立独行的猪", "王小波"}
			};

	int i;

	FILE *fp;

	fp = fopen("data1.txt", "w");

	if(fp == NULL)
	{
		printf("fail to open file\n");
		return 1;
	}

	for(i=0; i<N; ++i)
	{
		fprintf(fp, "%-20s %-20s\n", x[i].name, x[i].author);
		printf("%-20s %-20s\n", x[i].name, x[i].author);
	}

	fclose(fp);

	return 0;
}

image

image

task1-2

#include<stdio.h>
#define N 5
#define M 80

typedef struct
{
	char name[M];
	char author[M];
}Book;

int main()
{
	Book x[N];
	int i;

	FILE *fp;

	fp=fopen("data1.txt","r");

	if(fp==NULL)
	{
		printf("fail to open file\n");
		return 1;
	}

	for(i=0;i<N;++i)
	{
		fscanf(fp,"%s%s\n",x[i].name,x[i].author);
		printf("%-20s%-20s\n",x[i].name,x[i].author);
	}

	fclose(fp);

	return 0;
}

image
line35,从文件中读取图书名、图书作者时,为什么x[i].name和x[i].author前面没有地址符&?
%s对应输入一个字符串,需要提供一个字符数组来存储,数组名是一个地址,不用加&取地址。

task2

task2-1

#include <stdio.h>
#define N 5
#define M 80

typedef struct
{
	char name[M];
	char author[M];
}Book;

int main()
{
	Book x[N] = {	{"一九八四", "乔治.奥威尔"},
			{"美丽新世界", "赫胥黎"},
			{"昨日的世界", "斯蒂芬.茨威格"},
			{"万历十五年", "黄仁宇"},
			{"一只特立独行的猪", "王小波"}
			};

	int i;
	FILE *fp;

	fp = fopen("data2.dat", "wb");

	if(fp == NULL)
	{
		printf("fail to open file\n");
		return 1;
	}

	fwrite(x, sizeof(Book), N, fp);

	fclose(fp);

return 0;
}

image

task2-2

#include<stdio.h>
#define N 5
#define M 80

typedef struct
{
	char name[M];
	char author[M];
}Book;

int main()
{
	Book x[N];
	int i;

	FILE *fp;

	fp = fopen("data2.dat", "rb");

	if(fp == NULL)
	{
		printf("fail to open file\n");
		return 1;
	}

	fread(x, sizeof(Book), N, fp);

	for(i=0; i<N; ++i)
	printf("%-20s%-20s\n", x[i].name, x[i].author);

	fclose(fp);

return 0;
}

image
1. 在当前路径下,生成了一个文件名为data2.dat的数据文件。
2. 用文本编辑器打开后,其内容变为一行一列的存储形式。

task3

task3-2

#include<stdio.h>

int main()
{
	FILE *fp;
	char ch;
	int count=0;

	fp=fopen("data3_1.txt","r");

	if(fp==NULL)
	{
		printf("fail to open file\n");
		return 1;
	}

	while(!feof(fp))
	{
		ch=fgetc(fp);
		if(ch && ch!='\0'&&ch!=' '&&ch!='\n'&&ch!='	')
        count++;
	}

	fclose(fp);

	printf("data3_1.txt中共包含字符数:%d",count);

	return 0;
}

image

task5

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

#define N 10
typedef struct
{
	long int id;
	char name[20];
	float objective;
	float subjective; 
	float sum;
	char level[10];
}STU;

void input(STU s[], int n);
void output(STU s[], int n);
void process(STU s[], int n);

int main()
{
	STU stu[N];
	printf("从文件读入%d个考生信息: 准考证号,姓名,客观题得分(<=40),操作得分(<=60)\n", N);
	input(stu, N);

	printf("\n对考生信息进行处理: 计算总分,确定等级\n");
	process(stu, N);

	printf("\n打印考生完整信息, 并保存到文件中");
	output(stu, N);

	return 0;
}

void input(STU s[], int n)
{
	int i;
	FILE *fin;

	fin = fopen("examinee.txt", "r");
	if (fin == NULL)
	{
		printf("fail to open file\n");
		exit(0);
	}

	while (!feof(fin))
	{
		for (i = 0; i < n; i++)
		fscanf(fin, "%ld %s %f %f", &s[i].id, s[i].name,&s[i].objective, &s[i].subjective);
	}

	fclose(fin);
}

void output(STU s[],int n)
{
	FILE *fout;
	int i;

	printf("\n");
	printf("准考证号\t姓名\t客观题得分\t操作题得分\t总分\t\t等级\n");

	for(i=0;i<n;i++)
	printf("%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t\t%s\n", s[i].id,s[i].name, s[i].objective, s[i].subjective, s[i].sum, s[i].level);
	fout = fopen("result.txt", "w");

	if (!fout)
	{
		printf("fail to open or create result.txt\n");
		exit(0);
	}

	fprintf(fout, "准考证号\t姓名\t客观题得分\t操作题得分\t总分\t\t等级\n");

	for (i = 0; i < n; i++)
	fprintf(fout, "%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t\t%s\n", s[i].id,s[i].name, s[i].objective, s[i].subjective, s[i].sum, s[i].level);

	fclose(fout);
}

void process(STU s[],int n)
{
	STU t;
	int i,j;

	for(i=0; i<n; i++)
	{
		s[i].sum=s[i].objective+s[i].subjective;
	}

	for(i=0; i<n; i++)
		for(j=0;j<n-i-1;j++)
		if(s[j].sum<s[j+1].sum)
		{
			t=s[j];
			s[j]=s[j+1];
			s[j+1]=t;
		}

for(i=0;i<n;i++)
	{
		if((i+1)<=n*0.1)
		strcpy(s[i].level,"优秀");

		else if((i+1)>n*0.1&&(i+1)<=n*0.5)
		strcpy(s[i].level,"合格");

		else
		strcpy(s[i].level,"不合格");
	}
}

image
image

task6

#include<stdio.h>
#include<time.h>
#include<stdlib.h>

#define N 5
#define M 80

typedef struct
{
	long int id;
	char name[M];
	char clas[M];
}STU;

int main()
{
	STU s[M];

	srand(time(0));

	FILE *fp,*fq;

	fp=fopen("list.txt","r");
	fq=fopen("lucky.txt","w+");

	int i,j,m,q;

	for(i=0;i<M;i++)
	{
	fscanf(fp,"%ld%s%s",&s[i].id,s[i].name,s[i].clas);
	}

	for(j=0;j<N;j++)
	{
	m=rand()%80;

	for(i=0;i<M;i++)
		{
			if(m==s[i].id%100)
			{
				printf("%ld%-20s%-20s\n",s[i].id,s[i].name,s[i].clas);
				fprintf(fq,"%ld\t%20s\t%20s\t\n",s[i].id,s[i].name,s[i].clas);
			}
		}
	}

	fclose(fp);
	fclose(fq);

	return 0;
}

image
image

标签:fp,文件,int,char,define,Book,实验,include,结构
来源: https://www.cnblogs.com/jieye/p/16348179.html

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