标签:状态 State NUMBER CHAR STATE CharType EXP 转移
type State int type CharType int const ( STATE_INITIAL State = iota STATE_INT_SIGN STATE_INTEGER STATE_POINT STATE_POINT_WITHOUT_INT STATE_FRACTION STATE_EXP STATE_EXP_SIGN STATE_EXP_NUMBER STATE_END ) const ( CHAR_NUMBER CharType = iota CHAR_EXP CHAR_POINT CHAR_SIGN CHAR_SPACE CHAR_ILLEGAL ) func toCharType(ch byte) CharType { switch ch { case '0', '1', '2', '3', '4', '5', '6', '7', '8', '9': return CHAR_NUMBER case 'e', 'E': return CHAR_EXP case '.': return CHAR_POINT case '+', '-': return CHAR_SIGN case ' ': return CHAR_SPACE default: return CHAR_ILLEGAL } } func isNumber(s string) bool { transfer := map[State]map[CharType]State{ STATE_INITIAL: map[CharType]State{ CHAR_SPACE: STATE_INITIAL, CHAR_NUMBER: STATE_INTEGER, CHAR_POINT: STATE_POINT_WITHOUT_INT, CHAR_SIGN: STATE_INT_SIGN, }, STATE_INT_SIGN: map[CharType]State{ CHAR_NUMBER: STATE_INTEGER, CHAR_POINT: STATE_POINT_WITHOUT_INT, }, STATE_INTEGER: map[CharType]State{ CHAR_NUMBER: STATE_INTEGER, CHAR_EXP: STATE_EXP, CHAR_POINT: STATE_POINT, CHAR_SPACE: STATE_END, }, STATE_POINT: map[CharType]State{ CHAR_NUMBER: STATE_FRACTION, CHAR_EXP: STATE_EXP, CHAR_SPACE: STATE_END, }, STATE_POINT_WITHOUT_INT: map[CharType]State{ CHAR_NUMBER: STATE_FRACTION, }, STATE_FRACTION: map[CharType]State{ CHAR_NUMBER: STATE_FRACTION, CHAR_EXP: STATE_EXP, CHAR_SPACE: STATE_END, }, STATE_EXP: map[CharType]State{ CHAR_NUMBER: STATE_EXP_NUMBER, CHAR_SIGN: STATE_EXP_SIGN, }, STATE_EXP_SIGN: map[CharType]State{ CHAR_NUMBER: STATE_EXP_NUMBER, }, STATE_EXP_NUMBER: map[CharType]State{ CHAR_NUMBER: STATE_EXP_NUMBER, CHAR_SPACE: STATE_END, }, STATE_END: map[CharType]State{ CHAR_SPACE: STATE_END, }, } state := STATE_INITIAL for i := 0; i < len(s); i++ { typ := toCharType(s[i]) if _, ok := transfer[state][typ]; !ok { return false } else { state = transfer[state][typ] } } return state == STATE_INTEGER || state == STATE_POINT || state == STATE_FRACTION || state == STATE_EXP_NUMBER || state == STATE_END }
作者:LeetCode-Solution
链接:https://leetcode-cn.com/problems/biao-shi-shu-zhi-de-zi-fu-chuan-lcof/solution/biao-shi-shu-zhi-de-zi-fu-chuan-by-leetcode-soluti/
来源:力扣(LeetCode)
著作权归作者所有。商业转载请联系作者获得授权,非商业转载请注明出处。
标签:状态,State,NUMBER,CHAR,STATE,CharType,EXP,转移 来源: https://www.cnblogs.com/rsapaper/p/16223125.html
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