标签:arr TreeNode String offer dataList 28 ----- str root
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Codec {
public String serialize(TreeNode root) {
return rserialize(root, "");
}
public TreeNode deserialize(String data) {
String[] dataArray = data.split(",");
List<String> dataList = new LinkedList<String>(Arrays.asList(dataArray));
return rdeserialize(dataList);
}
public String rserialize(TreeNode root, String str) {
if (root == null) {
str += "None,";
} else {
str += str.valueOf(root.val) + ",";
str = rserialize(root.left, str);
str = rserialize(root.right, str);
}
return str;
}
public TreeNode rdeserialize(List<String> dataList) {
if (dataList.get(0).equals("None")) {
dataList.remove(0);
return null;
}
TreeNode root = new TreeNode(Integer.valueOf(dataList.get(0)));
dataList.remove(0);
root.left = rdeserialize(dataList);
root.right = rdeserialize(dataList);
return root;
}
}
// Your Codec object will be instantiated and called as such:
// Codec codec = new Codec();
// codec.deserialize(codec.serialize(root));
class Solution {
List<String> rec;
boolean[] vis;
public String[] permutation(String s) {
int n = s.length();
rec = new ArrayList<String>();
vis = new boolean[n];
char[] arr = s.toCharArray();
Arrays.sort(arr);
StringBuffer perm = new StringBuffer();
backtrack(arr, 0, n, perm);
int size = rec.size();
String[] recArr = new String[size];
for (int i = 0; i < size; i++) {
recArr[i] = rec.get(i);
}
return recArr;
}
public void backtrack(char[] arr, int i, int n, StringBuffer perm) {
if (i == n) {
rec.add(perm.toString());
return;
}
for (int j = 0; j < n; j++) {
if (vis[j] || (j > 0 && !vis[j - 1] && arr[j - 1] == arr[j])) {
continue;
}
vis[j] = true;
perm.append(arr[j]);
backtrack(arr, i + 1, n, perm);
perm.deleteCharAt(perm.length() - 1);
vis[j] = false;
}
}
}
标签:arr,TreeNode,String,offer,dataList,28,-----,str,root 来源: https://blog.csdn.net/DUANJIAWEIDUANJIAWEI/article/details/121935853
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