如何在Castle.DynamicProxy中使用IInterceptor?(How use IInterceptor in Castle.DynamicProxy?)

2021-09-28 23:02:44 阅读：202 来源： 互联网

标签：IInvocation DynamicProxy IInterceptor int void class invocation Castle public

参考：https://www.it1352.com/1796724.html

我写了一个这样的例子

简单计算器类:

public class Calculator
{
    public int Add(int a, int b)
    {
        return a + b;
    }
}

实现了DynamicProxy提供的"IInterceptor"

 [Serializable]
public abstract class Interceptor : IInterceptor
{
    public void Intercept(IInvocation invocation)
    {
        ExecuteBefore(invocation);
        invocation.Proceed();
        ExecuteAfter(invocation);

    }
    protected abstract void ExecuteAfter(IInvocation invocation);
    protected abstract void ExecuteBefore(IInvocation invocation);
}

创建了一个Interceptor类，并从"Interceptor"类继承

    public class CalculatorInterceptor : Interceptor
{
    protected override void ExecuteBefore(Castle.DynamicProxy.IInvocation invocation)
    {
        Console.WriteLine("Start");
    }

    protected override void ExecuteAfter(Castle.DynamicProxy.IInvocation invocation)
    {
        Console.WriteLine("End");
    }
}

但是当我使用它不起作用时！！

static void Main(string[] args)
    {
        ProxyGenerator generator = new ProxyGenerator();
        Calculator c = generator.CreateClassProxy<Calculator>(new CalculatorInterceptor());
        var r = c.Add(11, 22);
        Console.WriteLine(r);
        Console.ReadKey();
    }

我例外地看到了这样的东西:

START
33
END

但仅显示

我该如何纠正?！

解决方案

尝试将方法Add设为虚拟.

public class Calculator
{
    public virtual int Add(int a, int b)
    {
        return a + b;
    }
}

代理生成器创建一个继承Calculator的新类.因此，方法Add获得重写以使拦截成为可能.

原文

I wrote an example like this

Simple Calculator class :

public class Calculator
{
    public int Add(int a, int b)
    {
        return a + b;
    }
}

implemented "IInterceptor" that provided by DynamicProxy

 [Serializable]
public abstract class Interceptor : IInterceptor
{
    public void Intercept(IInvocation invocation)
    {
        ExecuteBefore(invocation);
        invocation.Proceed();
        ExecuteAfter(invocation);

    }
    protected abstract void ExecuteAfter(IInvocation invocation);
    protected abstract void ExecuteBefore(IInvocation invocation);
}

Created an Interceptor class and inherited from "Interceptor" class

    public class CalculatorInterceptor : Interceptor
{
    protected override void ExecuteBefore(Castle.DynamicProxy.IInvocation invocation)
    {
        Console.WriteLine("Start");
    }

    protected override void ExecuteAfter(Castle.DynamicProxy.IInvocation invocation)
    {
        Console.WriteLine("End");
    }
}

but when I used it NOT working !!!

static void Main(string[] args)
    {
        ProxyGenerator generator = new ProxyGenerator();
        Calculator c = generator.CreateClassProxy<Calculator>(new CalculatorInterceptor());
        var r = c.Add(11, 22);
        Console.WriteLine(r);
        Console.ReadKey();
    }

I excepted to see something like this :

START
33
END

but only show

How I can correct it ?!

解决方案

Try to make the method Add virtual.

public class Calculator
{
    public virtual int Add(int a, int b)
    {
        return a + b;
    }
}

The proxy generator creates a new class inheriting Calculator. Thus, the method Add gets an override to make interception possible.

获得方法名

System.Reflection.MethodBase.GetCurrentMethod().Name;

标签：IInvocation,DynamicProxy,IInterceptor,int,void,class,invocation,Castle,public
来源： https://www.cnblogs.com/bruce1992/p/15350544.html

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如何在Castle.DynamicProxy中使用IInterceptor?(How use IInterceptor in Castle.DynamicProxy?)