标签:pre head ListNode cur val Duplicates List Day2 next
Solution 1:
It is a sorted linked list, we can delete all duplicates one by one,but at first I made a mistake in case [0,0,0,0,0] , because I set pre number 0,therefore I turn it to be -99,that is okay.
class Solution {
public:
ListNode* deleteDuplicates(ListNode* head) {
ListNode *pre = new ListNode(-99,head);
ListNode *cur = head;
while(head){
if(head->val == pre->val){
pre->next = head->next;
head = head->next;
}else{
pre = head;
head = head->next;
}
}
return cur;
}
};
Python version
class Solution:
def deleteDuplicates(self, head: ListNode) -> ListNode:
if not head:
return head
cur = head
while cur.next:
if cur.next.val == cur.val:
cur.next = cur.next.next
cur = cur.next
else:
cur = cur.next
return head
标签:pre,head,ListNode,cur,val,Duplicates,List,Day2,next 来源: https://blog.csdn.net/qq_39679069/article/details/120383834
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