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基于Hibernate实现CRUD

2021-06-16 20:34:16  阅读:160  来源: 互联网

标签:基于 Hibernate CRUD System session user sc tuser0 out


crud.excecuteQuery(getSession());
		Session session= getSession();
		while(true){
		  System. out. println(' CRUD开始---请输入你的操作"):
		  System. out. println(" 1.添加  2.制除  3.修改4.查找  5.退出”):Scanner sc=new Scanner (System. in):int choice=sc. nextInt();
		  switch (choice){
		  	case 1: crud.doRead(session); 
		  		break;
		  	case 2: main.doDelete(session); 
		  		break;
		  	case 3: main.doUpdate(session) ; 
		  		break;
		  	case 4: main.doCreat(session) ; 
		  		break:
		    case 5: return;
		  }
		}
public void doRead (Session session) {
		Transaction tx=session. beginTransaction();
		Scanner sc=new Scanner(System.in);
		User user=new User();
		System.out.println("请输入用户姓名");user.setUserName(sc.next());
		System.out,println("请输入用户年龄");user.setUserAge(sc.next());
		System.out.println("请输入用户性别,男女”);
		System.out.println("确认添加--y,退出--n");
		if(sc.next().equals(" y")){
			session.save(user);
			tx.commit();
			return;
		} else {
			return;
		}
	}

 运行结果

 

 

 

 添加语句

Hibernate:
insert
into
t_ user
(username, age, gender,uid)
values
tuser0_ .uid as uid0_0_ 0_,
tuser0_.username as username0_1_ 0_ ,
tuser0_.age as age0_2_ 0_,  
tuser0_.gender as gender0_3_ 0_,
from
 		hibernate.t_user tuser0_
left outer join
  	t_ user tuserentitl_
  	on tuser0_ . uid=tusertl . uid
where
  tuser0_ . uid=?

 运行结果

 

 

 

 

 

 删除

public void doDelete(Session session){
		Transaction tx = session.beginTransactiom();
		Scanner sc=new Scanner (System.in):
		Query query = session.createQuery("from User ");
		List<User>. user=query.list();
		for(User user:users) {
System.out.println( user.getUid() + "-----" + user.getUsername() + "-----" + 			user.getAge() + "-----" + user.getGender());
}
		System.out.println("请选择要删除的用户");
		User Duser=session.get(User.class.sc.nestInt());
		System.out.printin("确认要删除? ");
		if(sc.next().equals("y"){
			session.remove(Duser);
			tx.commit();
		} else {
			return;
		}
}

运行结果

Hibernate:
select
tuser0_ .uid as uid0_0_ 0_,
tuser0_.username as username0_1_ 0_ ,
tuser0_.age as age0_2_ 0_,  
tuser0_.gender as gender0_3_ 0_,
from
 		hibernate.t_user tuser0_
where
 	 tuser0_ . uid=?

 

 运行结果

 

修改

public void doUpdate(Session session){
		Transaction tx=session.beginTransaction();
		Scanner sc=new Scanner(System.in);
		Query query = session.createQuery( s:"from User");
		List<User> users=query.list();
		for(User user:users) {
	System.out.println(user.getUid() + "-----" + user.getUsername() + "-----" + 			user.getAge() + "-----" + user.getGender());
		}
		System.out.println("请选择你要修改的用户");
		User Uuser=session.get(User.class.sc.nextInt());
		System.out.println("请输入修改的姓名");
		Uuser.setUserName(sc.next());
		System.out.println("请输入年龄");
		Uuser.setAge(sc.next());
		System.out.printIn("请输入性别");
		Uuser.setGender(sc.next());
		System.out.printIn("确认要修改?");
		if(sc.next() equals("y")) {
			session.update(Uuser);
			tx. commit();
		} else {
			return;
		}
	}

运行结果

 

 查询

public void doRead(Session session) {
	Transaction tx=session.beginTransaction();
	Scanner sc=new Scanner(System.in) ;
	Query query = session. createQuery(s:" from User");
	List<User> users=query.list();
	tx.commit();
    for(User user:users) {
System.out.println(user.getUid() + "-----" + user.getUsername() + "-----" + 	user.getAge() + "-----" + user.getGender());
    	System.out.println("退出请输入0");
    	while(sc. nextInt()==0) {
    		return;
    	}
	}

  

 查询语句

Hibernate:
select
  		tusert0_ .uid as uid0_0_,
tuser0_.username as username0_1_ 0_ ,
tuser0_.age as age0_2_ 0_,  
tuser0_.gender as gender0_3_ 0_,
from
 	hibernate.t_user tuser0_

运行结果

 

标签:基于,Hibernate,CRUD,System,session,user,sc,tuser0,out
来源: https://www.cnblogs.com/center-cc/p/14890922.html

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