标签：drunk python Naive number 分类器 failed ex expected study
简单实现来自b站大神的视频讲解：https://www.bilibili.com/video/BV1qs411a7mT
详情可以看视频链接，讲的非常好。
1 # coding=utf-8
2 from __future__ import division
3 from numpy import array
4
5 def naive_bs(failed_number, drunk_number, shopping_number, study_number, expected_drunk, expected_shopping, expected_study):
6
7 ex_failed = 0
8 ex_not_failed = 0
9
10 for i in range(0, len(failed_number)):
11 if study_number[i] == 0:
12 ex_failed = ex_failed + 1
13 elif study_number[i] == 1:
14 ex_not_failed = ex_not_failed + 1
15
16 # 统计p(x?|y)出现的概率
17 # 计算不同情况
18 aa = 0
19 bb = 0
20 for i in range(0, len(drunk_number)):
21 if expected_drunk == drunk_number[i] and failed_number[i] == 1:
22 aa = aa + 1
23 elif expected_drunk == drunk_number[i] and failed_number[i] == 0:
24 bb = bb + 1
25 p_aa = aa / ex_failed #x1|y x1=0,y=1
26 p_bb = bb / ex_not_failed#x1|y x1=0,y=0
27
28 aaa = 0
29 bbb = 0
30
31 for i in range(0, len(shopping_number)):
32 if expected_shopping == shopping_number[i] and failed_number[i] == 1:
33 aaa = aaa + 1
34 elif expected_shopping == shopping_number[i] and failed_number[i] == 0:
35 bbb = bbb + 1
36 p_aaa = aaa / ex_failed
37 p_bbb = bbb / ex_not_failed
38
39 a4 = 0
40 b4 = 0
41 for i in range(0, len(study_number)):
42 if expected_study == study_number[i] and failed_number[i] == 1:
43 a4 = a4 + 1
44 elif expected_study == study_number[i] and failed_number[i] == 0:
45 b4 = b4 + 1
46 p_a4 = a4 / ex_failed
47 p_b4 = b4 / ex_not_failed
48
49 # print("aa:%s , aaa=%s a4=%s" % ( aa,aaa,a4))
50 # print("p_aa:%s , aaa=%s a4=%s" % (p_aa, p_aaa, p_a4))
51 # print("bb:%s , bbb=%s b4=%s" % (bb, bbb, b4))
52 # print("p_bb:%s , bbb=%s b4=%s" % (p_bb, p_bbb, p_b4))
53 final_failed_p = p_aa * p_aaa* p_a4 * ex_failed / len(failed_number)
54 final_not_p = p_bb * p_bbb * p_b4* ex_not_failed / len(failed_number)
55 print("挂科的概率=%s"%(final_failed_p))
56 print("不挂科的概率=%s"%(final_not_p))
57 if final_not_p>final_not_p:
58 print("预测会挂科")
59 else:
60 print("预测不会挂科")
61
62
63 if __name__ == "__main__":
64 failed_number = [1, 0, 0, 1, 1, 0, 0, 1]
65 drunk_number = [1, 0, 1, 1, 0, 0, 0, 0]
66 shopping_number=[1, 0, 0, 0, 1, 1, 1, 0]
67 study_number = [0, 1, 1, 0, 0, 1, 0, 1]
68
69 expected_drunk = 0
70 expected_shopping = 0
71 expected_study = 1
72 #不喝酒 不逛街 学习 的挂科概率
73 print(drunk_number, study_number, shopping_number)
74 naive_bs(failed_number, drunk_number, shopping_number,study_number,
75 expected_drunk, expected_shopping,expected_study)
代码和自己做的PPT百度云链接：
链接：https://pan.baidu.com/s/1WKn9sY295Qp9JSn3It0yxg
提取码：23cd
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标签：drunk,python,Naive,number,分类器,failed,ex,expected,study 来源： https://www.cnblogs.com/fudanxi/p/13922673.html
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