标签:serialization json-net expandoobject dynamicobject c
我有一个从DynamicObject类派生的类.调用JsonConvert.SertializeObject时,不会动态化任何动态属性.
类定义为
public class Component : DynamicObject
{
// The inner dictionary.
public Dictionary<string, object> dictionary
= new Dictionary<string, object>();
[JsonProperty(PropertyName = "id")]
public string Id { get; set; }
// If you try to get a value of a property
// not defined in the class, this method is called.
public override bool TryGetMember (
GetMemberBinder binder, out object result)
{
// Converting the property name to lowercase
// so that property names become case-insensitive.
string name = binder.Name.ToLower();
// If the property name is found in a dictionary,
// set the result parameter to the property value and return true.
// Otherwise, return false.
return dictionary.TryGetValue(name, out result);
}
// If you try to set a value of a property that is
// not defined in the class, this method is called.
public override bool TrySetMember (
SetMemberBinder binder, object value)
{
// Converting the property name to lowercase
// so that property names become case-insensitive.
dictionary[binder.Name.ToLower()] = value;
// You can always add a value to a dictionary,
// so this method always returns true.
return true;
}
}
然后我这样做
dynamic component = new Component();
component.test = "123";
JsonConvert.SerializeObject(component);
解决方法:
您需要覆盖DynamicObject.GetDynamicMemberNames
:
public override IEnumerable<string> GetDynamicMemberNames()
{
return dictionary.Keys;
}
标签:serialization,json-net,expandoobject,dynamicobject,c 来源: https://codeday.me/bug/20191109/2012521.html
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