标签:inheritance django-forms python django
我有这个ModelForm:
class Event(forms.ModelForm):
def __init__(self, *args, **kwargs):
super(Event, self).__init__(*args, **kwargs)
##Here make some changes such as:
self.helper = FormHelper()
self.helper.form_method = 'POST'
##Many settings here which **i don't want to rewrite in 10 child classes**
class Meta:
model = Event
exclude = something...
widgets = some settings here also.
而这个子ModelForm:
class UpgradedEvent(Event):
def __init__(self, *args, **kwargs):
super(UpgradedEvent,self).__init__(*args,**kwargs)
class Meta(Event.Meta):
model = UpgradedEvent
UpgradedEvent是事件模型的子级,但具有一些额外的字段.
如何将所有设置从事件表单继承到UpgradedEvent FORM中?
运行上面的代码时,它将呈现“事件”表单.有没有办法只继承__init__内部的设置?
EDIT
查看答案,它很好用,但请记住:
您需要在子类中创建另一个FormHelper实例,否则它将无法正常工作.因此,子类应类似于:
class UpgradedEvent(Event):
def __init__(self, *args, **kwargs):
super(UpgradedEvent,self).__init__(*args,**kwargs)
self.helper = FormHelper()
class Meta(Event.Meta):
model = UpgradedEvent
解决方法:
创建FormWithSettings,它将保留表单类的通用设置并继承它
class FormWithSettings(forms.ModelForm):
def __init__(self, *args, **kwargs):
super(FormWithSettings, self).__init__(*args, **kwargs)
##Here make some changes such as:
self.helper = FormHelper()
self.helper.form_method = 'POST'
##Many settings here which **i don't want to rewrite in 10 child classes**
class Meta:
exclude = something...
widgets = some settings here also.
class EventForm(FormWithSettings):
def __init__(self, *args, **kwargs):
super(EventForm, self).__init__(*args,**kwargs)
class Meta(FormWithSettings.Meta):
model = Event
class UpgradedEventForm(FormWithSettings):
def __init__(self, *args, **kwargs):
super(UpgradedEventForm, self).__init__(*args,**kwargs)
class Meta(FormWithSettings.Meta):
model = UpgradedEvent
标签:inheritance,django-forms,python,django 来源: https://codeday.me/bug/20191025/1926435.html
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