我想知道如何安排动态(自动填充数据)功能在保存的时间每天自动运行？
假设我有一个表单,一旦单击该按钮,它就会将数据发送到函数,该函数会发布数据.我只想自动化,这样我就不必按下按钮了.
<ul>
<?php
foreach($Class->retrieveData as $data)
{
<form method="post" action="">
<li>
<input type="hidden" name="name">'.$data['name'].'<br/>
<input type="hidden" name="description">'.$data['description'].'<br/>
<input type="submit" name="post_data" value="Post">
</li>
</form>
}
?>
</ul>
现在,表单将数据传递给函数.
if(isset($_POST['post_data'])) // if post_data button is clicked then it runs myFunction()
{
myFunction();
}
myFunction()
{
$name = $_POST['name'];
$description = $_POST['description'];
}
我尝试了以下操作,但问题是Cron Job只能运行整个.php文件,而我正在检索从MySQL运行的已保存时间.
foreach($Class->getTime() as $timeData)
{
$timeHour = $timeData['timeHour'];
$timeMinute = $timeData['timeMinute'];
$hourMin = date('H:i');
$timeData = ''.$timeHour.':'.$timeMinute.'';
if($hourMin == $timeData)
{
run myFunction.
}
}
$hourMin是当前小时：分钟,它与从Mysql自动运行的已保存时间相匹配.因此,如果$hourMin == $timeData,那么该函数将运行.
如果$hourMin等于$timeData,如何运行Cron Job来自动运行myFunction()？
所以…
List 1 = is to be runned at 10am
List 2 = is to be runned at 12pm
List 3 = is to be runned at 2pm
上午10点,下午12点,下午2点是从MySQL检索但是基于每个列表ID的$timeHour和$timeMinute.
编辑
@randomSeed,
1) I can schedule cron jobs.
2) $name and $description will all be arrays, so the following is what I am trying to accomplish.
$name = array(
'Jon',
'Steven',
'Carter'
);
$description = array(
'Jon is a great person.',
'Steven has an outgoing character.',
'Carter is a horrible person.'
);
如果预定的时间是正确的,我想解析$name和$description中的第一个数组.
在数据库中,我有以下内容
postDataTime table
+----+---------+----------+------------+--------+
| iD | timeDay | timeHour | timeMinute | postiD |
+--------------------------------------+--------+
| 1 | * | 9 | 0 | 21 |
|----|---------|----------|------------|--------|
| 2 | * | 10 | 30 | 22 |
|----|---------|----------|------------|--------|
| 3 | * | 11 | 0 | 23 |
+----|---------+----------+------------+--------+
iD = auto incremented on upload.
timeDay = * is everyday (cron job style)
timeHour = Hour of the day to run the script
timeMinute = minute of the hour to run script
postiD = this is the id of the post that is located in another table (n+1 relationship)
如果难以理解.. what is quinoa
if(time() == 10:30(time from MySQL postiD = 22))
{
// run myFunction with the data that is retrieved for that time ex:
$postiD = '22';
$name = 'Steven';
$description = 'Steven has an outgoing character.';
// the above is what will be in the $_POST from the form and will be
// sent to the myFunction()
}
我只想根据保存到MySQL的时间安排所有内容,就像我在最顶层显示的那样(postDataTime表). (我会展示我曾经尝试过的东西,但是我已经搜索了无数个小时的例子来说明我想要完成的事情,但我找不到任何东西,我尝试的东西也不起作用.)
我以为我可以使用exec()函数,但从它看起来不允许我运行函数,否则我会做以下..
$time = '10:30';
if($time == time())
{
exec(myFunction());
}
解决方法:
你有2种方法,虽然只有一种方法可以完成你想做的事情;
>第一种方式要求您具有更改cron-jobs服务器端的访问权限和权限(例如通过PHP或其他方式).根据操作系统有什么教程：Win,Nix
>第二种方式将做一些接近你想要的东西,但没有分钟精度,你将在每个周期最多2分钟松动. (见下面的exaplanation).
第一路完美的方式
>只要用户点击表单,就会使用所需的数据时间为该用户创建一个唯一的cron-task.
if you don’t have those privileges you can use 3d part service like
07002 they also offer a Free version with limited
query. they also provide a 07003 method to manage (CRUDE)
cron-tasks.
第二种方式不完美的方式
>添加一个新的VARCHAR列,我今天用它来调用它,我们将确保该任务每天只运行一次.
–
+----+---------+----------+------------+--------+----------+
| iD | timeDay | timeHour | timeMinute | postiD | today |
+--------------------------------------+--------+----------+
| 1 | * | 9 | 0 | 21 | 30-05-04 |
|----|---------|----------|------------|--------|----------+
| 2 | * | 10 | 30 | 22 | |
|----|---------|----------|------------|--------|----------+
| 3 | * | 11 | 0 | 23 | |
+----|---------+----------+------------+--------+----------+
>之后创建一个我称之为crontask.php的php文件,我们将每隔5分钟调用一次
>将此添加到您的cronjob面板：
> 0,5 * * * * /usr/bin/php /www/virtual/username/crontask.php\u0026gt; / dev / null 2>& 1
>在crontask.php文件中
–
<?php
// include() Database Config file here with mysql_connect etc...
// include() the required files ex. the file where myFunction reside...
$cron_cycle = 5; // set it equal to what used in cron command-line
$today = date('Y-m-d');
if($result = mysql_query("SELECT * FROM postDataTime WHERE today != '{$today}'")){
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
$postID = $row['postID'];
$timeHour = (int) $row['timeHour'];
$current_hours = (int) date('H'); // current hours
$current_minutes = (int) date('i'); // current minutes
$timeMinute = (int) $row['timeMinute'];
// force to run at the closest cycle
$timeMinute = ($timeMinute % $cycle === 0) ? $timeMinute : toCloser($timeMinute, $cron_cycle);
if( $current_hours === $timeHour && $current_minutes === $timeMinute ){
// ensure that we have already runned a cron for this user...
mysql_query("UPDATE postDataTime SET today = '{$today}' WHERE postID = '{$postID}'");
myFunction($postID);
}
}
}
function toCloser($n,$x=5) {
$j = (round($n)%$x === 0) ? round($n) : (round(($n+$x/2)/$x)*$x);
return ($j-$n) >= round($x/2) ? ($j-$x) : $j;
}
?>
功能说明：
假设cron shedule每5分钟运行一次,lat表示我们在20:00,现在cron将在20：05,20：10,20：15,20：20运行,依此类推……
然后在我们的数据库中假设我们有那些时间
Jonh : 20:05,
Mario : 20:32,
luke : 20:48,
David : 20:57,
Jimmy : 20:06,
Eddy : 20:16
当脚本检查时,它将运行如下：
at 20:05 -> run 20:05 Jonh, 20:06 Jimmy
at 20:10 -> run null
at 20:15 -> run 20:16 Eddy
at 20:20 -> run null
and so on....
如你所见,你会在最糟糕的情况下每次2分钟松动.我认为这很公平！
标签：cron-task,php,mysql,cron 来源： https://codeday.me/bug/20191006/1861670.html
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