标签:python multithreading login pyqt4 pickle
我正在尝试创建一个使用设置和Gui模块的用户系统,当GUI模块请求使用pickle加载文件时,我不断收到属性错误.这是来自设置模块:
import pickle
import hashlib
class User(object):
def __init__(self, fname, lname, dob, gender):
self.firstname = fname
self.lastname = lname
self._dob = dob
self.gender = gender
self.type = 'General'
self._username = ''
self._hashkey = ''
def Report(self):
print("Full Name: {0} {1}\nDate of Birth: {2}\nGender: {3}\nAccess Level: {4}".format(self.firstname,self.lastname, self._dob, self.gender, self.type))
print(self._username)
def Genusername(self):
self._username = str(str(self._dob)[:2] + self.firstname[:2] + self.lastname[:2])
saveUsers(users)
def Genhashkey(self, password):
encoded = password.encode('utf-8','strict')
return hashlib.sha256(encoded).hexdigest()
def Verifypassword(self, password):
if self._hashkey == self.Genhashkey(password):
return True
else:
return False
class SAdmin(User):
def __init__(self, fname, lname, dob, gender):
super().__init__(fname, lname, dob, gender)
self.type = 'Stock Admin'
class Manager(User):
def __init__(self, fname, lname, dob, gender):
super().__init__(fname, lname, dob, gender)
self.type = 'Manager'
def saveUsers(users):
with open('user_data.pkl', 'wb') as file:
pickle.dump(users, file, -1) # PICKLE HIGHEST LEVEL PROTOCOL
def loadUsers(users):
try:
with open('user_data.pkl', 'rb') as file:
temp = pickle.load(file)
for item in temp:
users.append(item)
except IOError:
saveUsers([])
def userReport(users):
for user in users:
print(user.firstname, user.lastname)
def addUser(users):
fname = input('What is your First Name?\n > ')
lname = input('What is your Last Name?\n > ')
dob = int(input('Please enter your date of birth in the following format, example 12211996\n> '))
gender = input("What is your gender? 'M' or 'F'\n >")
level = input("Enter the access level given to this user 'G', 'A', 'M'\n > ")
password = input("Enter a password:\n > ")
if level == 'G':
usertype = User
if level == 'A':
usertype = SAdmin
if level == 'M':
usertype = Manager
users.append(usertype(fname, lname, dob, gender))
user = users[len(users)-1]
user.Genusername()
user._hashkey = user.Genhashkey(password)
saveUsers(users)
def deleteUser(users):
userReport(users)
delete = input('Please type in the First Name of the user do you wish to delete:\n > ')
for user in users:
if user.firstname == delete:
users.remove(user)
saveUsers(users)
def changePass(users):
userReport(users)
change = input('Please type in the First Name of the user you wish to change the password for :\n > ')
for user in users:
if user.firstname == change:
oldpass = input('Please type in your old password:\n > ')
newpass = input('Please type in your new password:\n > ')
if user.Verifypassword(oldpass):
user._hashkey = user.Genhashkey(newpass)
saveUsers(users)
else:
print('Your old password does not match!')
def verifyUser(username, password):
for user in users:
if user._username == username and user.Verifypassword(password):
return True
else:
return False
if __name__ == '__main__':
users = []
loadUsers(users)
这是GUI模块:
from PyQt4 import QtGui, QtCore
import Settings
class loginWindow(QtGui.QDialog):
def __init__(self):
super().__init__()
self.initUI()
def initUI(self):
self.lbl1 = QtGui.QLabel('Username')
self.lbl2 = QtGui.QLabel('Password')
self.username = QtGui.QLineEdit()
self.password = QtGui.QLineEdit()
self.okButton = QtGui.QPushButton("OK")
self.okButton.clicked.connect(self.tryLogin)
self.cancelButton = QtGui.QPushButton("Cancel")
grid = QtGui.QGridLayout()
grid.setSpacing(10)
grid.addWidget(self.lbl1, 1, 0)
grid.addWidget(self.username, 1, 1)
grid.addWidget(self.lbl2, 2, 0)
grid.addWidget(self.password, 2, 1)
grid.addWidget(self.okButton, 3, 1)
grid.addWidget(self.cancelButton, 3, 0)
self.setLayout(grid)
self.setGeometry(300, 300, 2950, 150)
self.setWindowTitle('Login')
self.show()
def tryLogin(self):
print(self.username.text(), self.password.text())
if Settings.verifyUser(self.username.text(),self.password.text()):
print('it Woks')
else:
QtGui.QMessageBox.warning(
self, 'Error', 'Incorrect Username or Password')
class Window(QtGui.QMainWindow):
def __init__(self):
super().__init__()
if __name__ == '__main__':
app = QtGui.QApplication(sys.argv)
users = []
Settings.loadUsers(users)
if loginWindow().exec_() == QtGui.QDialog.Accepted:
window = Window()
window.show()
sys.exit(app.exec_())
每个用户都是一个类,并被放入一个列表,然后当我加载设置文件时,使用pickle保存列表,并验证登录一切正常,但是当我打开GUI模块并尝试验证它不让我,我得到的错误:
Traceback (most recent call last):
File "C:\Users`Program\LoginGUI.py", line 53, in <module>
Settings.loadUsers(users)
File "C:\Users\Program\Settings.py", line 51, in loadUsers
temp = pickle.load(file)
AttributeError: Can't get attribute 'Manager' on <module '__main__' (built-in)>
解决方法:
问题是你通过实际运行’Settings’模块来腌制在Settings中定义的对象,然后你试图从GUI模块中取消对象的取消.
请记住,pickle实际上并不存储有关如何构造类/对象的信息,并且在unpickling时需要访问该类.有关详细信息,请参见wiki on using Pickle.
在pkl数据中,您看到被引用的对象是__main __.管理器,因为当您创建pickle文件时,’Settings’模块是主要的(即您将’Settings’模块作为主脚本运行以调用addUser函数) .
然后,您尝试在’Gui’中取消选择 – 以便模块具有名称__main__,并且您正在该模块中导入Setting.所以当然Manager类实际上是Settings.Manager.但是pkl文件不知道这一点,并在__main__中查找Manager类,并抛出一个AttributeError,因为它不存在(Settings.Manager可以,但__main __.Manager不会).
这是一个最小的代码集来演示.
class_def.py模块:
import pickle
class Foo(object):
def __init__(self, name):
self.name = name
def main():
foo = Foo('a')
with open('test_data.pkl', 'wb') as f:
pickle.dump([foo], f, -1)
if __name__=='__main__':
main()
您运行上面的操作来生成pickle数据.
main_module.py模块:
import pickle
import class_def
if __name__=='__main__':
with open('test_data.pkl', 'rb') as f:
users = pickle.load(f)
您运行以上操作以尝试打开pickle文件,这会抛出与您看到的大致相同的错误. (略有不同,但我猜这是因为我在Python 2.7上)
解决方案是:
>通过显式导入,使类在顶级模块的命名空间(即GUI或main_module)中可用,或者
>您可以从与其打开的模块相同的顶级模块创建pickle文件(例如,从GUI调用Settings.addUser,或者从main_module调用class_def.main).这意味着pkl文件将对象保存为Settings.Manager或class_def.Foo,然后可以在GUI`main_module`命名空间中找到它们.
选项1示例:
import pickle
import class_def
from class_def import Foo # Import Foo into main_module's namespace explicitly
if __name__=='__main__':
with open('test_data.pkl', 'rb') as f:
users = pickle.load(f)
选项2示例:
import pickle
import class_def
if __name__=='__main__':
class_def.main() # Objects are being pickled with main_module as the top-level
with open('test_data.pkl', 'rb') as f:
users = pickle.load(f)
标签:python,multithreading,login,pyqt4,pickle 来源: https://codeday.me/bug/20190917/1809310.html
本站声明: 1. iCode9 技术分享网(下文简称本站)提供的所有内容,仅供技术学习、探讨和分享; 2. 关于本站的所有留言、评论、转载及引用,纯属内容发起人的个人观点,与本站观点和立场无关; 3. 关于本站的所有言论和文字,纯属内容发起人的个人观点,与本站观点和立场无关; 4. 本站文章均是网友提供,不完全保证技术分享内容的完整性、准确性、时效性、风险性和版权归属;如您发现该文章侵犯了您的权益,可联系我们第一时间进行删除; 5. 本站为非盈利性的个人网站,所有内容不会用来进行牟利,也不会利用任何形式的广告来间接获益,纯粹是为了广大技术爱好者提供技术内容和技术思想的分享性交流网站。