对于以下Google JSON-LD结构……
<script type="application/ld+json" id="datablock-1">
{
"@context": "http://schema.org/",
"@type": "Person",
"honorificPrefix": "Dr",
"givenName": "Albert",
"familyName": "Einstein",
"honorificSuffix": "PhD",
"jobTitle": "Professor of Physics",
"worksFor": [ {
"@type": "EducationalOrganization",
"department": "School of Science",
"parentOrganization": "Princeton University",
"address": [ {
"@type": "PostalAddress",
"streetAddress": "One Relativity Way",
"addressCountry": "USA" } ]
} ]
}
</script>
这个HTML JavaScript工作原理:
<body>
<dl><dt>Big Ideas</dt><dd id="dd-1"></dd></dl>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script>
var data = $("#datablock-1").html();
var json = JSON.parse(data);
var people = json["worksFor"];
for (i=0; i<=people.length; i++) {
var a=json["givenName"];
var b=json["familyName"];
var c=json["honorificSuffix"];
var d=json["worksFor"][i]["parentOrganization"];
$('#dd-1').append("<dd>"+a+" "+b+", "+c+". "+" "+d+"."+" "+"</dd>");
}
</script>
</body>
现在我需要在对象中更深入一级并添加有关“@type”的信息:“PostalAddress”.
但是这个HTML JavaScript不起作用:
<body>
<dl><dt>Big Ideas</dt><dd id="dd-1"></dd></dl>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script>
var data = $("#datablock-1").html();
var json = JSON.parse(data);
var people = json["worksFor"]["address"];
for (i=0; i<=people.length; i++) {
var a=json["givenName"];
var b=json["familyName"];
var c=json["honorificSuffix"];
var d=json["worksFor"][i]["parentOrganization"];
var e=json["worksFor"]["address"][i]["streetAddress"];
$('#dd-1').append("<dd>"+a+" "+b+", "+c+". "+" "+d+"."+" "+e+"</dd>");
}
</script>
</body>
我究竟做错了什么?如何纠正错误?
解决方法:
难道你不是只是从顶部跳到邮政地址,而不改变条件?我已经将你的人员变量名称改为works,因为这是你正在迭代的内容,因为它看起来不像你有一个人的列表atm.也许我错了?
<body>
<dl><dt>Big Ideas</dt><dd id="dd-1"></dd></dl>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script>
var data = $("#datablock-1").html();
var json = JSON.parse(data);
var worksFor= json["worksFor"];
for (i=0; i<=worksFor.length; i++) {
var a=json["givenName"];
var b=json["familyName"];
var c=json["honorificSuffix"];
var d=json["worksFor"][i]["parentOrganization"];
var e=json["worksFor"][i]["address"][0]["streetAddress"];//this line is changed
$('#dd-1').append("<dd>"+a+" "+b+", "+c+". "+" "+d+"."+e+"</dd>");
}
</script>
</body>
标签:json-ld,javascript,json 来源: https://codeday.me/bug/20190829/1762489.html
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