facebook sdk php示例无效

2019-07-08 22:30:00 阅读：165 来源： 互联网

我正在尝试为一个网站开发facebook登录,我尝试了用php-facebook-sdk给出的例子,即使在登录到facebook之后,即使在Facebook登录后它还没有显示注销网址,$user变量仍为0.

拨打$facebook-> getUser();功能总是返回0.

  require '../src/facebook.php';

// Create our Application instance (replace this with your appId and secret).
$facebook = new Facebook(array(
  'appId'  => 'xxx',
  'secret' => 'xxxx',
));

// Get User ID
$user = $facebook->getUser();

// We may or may not have this data based on whether the user is logged in.
//
// If we have a $user id here, it means we know the user is logged into
// Facebook, but we don't know if the access token is valid. An access
// token is invalid if the user logged out of Facebook.

if ($user) {
  try {
    // Proceed knowing you have a logged in user who's authenticated.
    $user_profile = $facebook->api('/me');
  } catch (FacebookApiException $e) {
    error_log($e);
    $user = null;
  }
}
print_r($user);
// Login or logout url will be needed depending on current user state.
if ($user) {
  $logoutUrl = $facebook->getLogoutUrl();
} else {
  $statusUrl = $facebook->getLoginStatusUrl();
  $loginUrl = $facebook->getLoginUrl();
}

// This call will always work since we are fetching public data.
$naitik = $facebook->api('/verity.vis');

?>
<!doctype html>
<html xmlns:fb="http://www.facebook.com/2008/fbml">
  <head>
    <title>php-sdk</title>
    <style>
      body {
        font-family: 'Lucida Grande', Verdana, Arial, sans-serif;
      }
      h1 a {
        text-decoration: none;
        color: #3b5998;
      }
      h1 a:hover {
        text-decoration: underline;
      }
    </style>
  </head>
  <body>
    <h1>php-sdk</h1>

    <?php if ($user): ?>
      <a href="<?php echo $logoutUrl; ?>">Logout</a>
    <?php else: ?>
      <div>
        Check the login status using OAuth 2.0 handled by the PHP SDK:
        <a href="<?php echo $statusUrl; ?>">Check the login status</a>
      </div>
      <div>
        Login using OAuth 2.0 handled by the PHP SDK:
        <a href="<?php echo $loginUrl; ?>">Login with Facebook</a>
      </div>
    <?php endif ?>

    <h3>PHP Session</h3>
    <pre><?php print_r($_SESSION); ?></pre>

    <?php if ($user): ?>
      <h3>You</h3>
      <img src="https://graph.facebook.com/<?php echo $user; ?>/picture">

      <h3>Your User Object (/me)</h3>
      <pre><?php print_r($user_profile); ?></pre>
    <?php else: ?>
      <strong><em>You are not Connected.</em></strong>
    <?php endif ?>

    <h3>Public profile of Naitik</h3>
    <img src="https://graph.facebook.com/verity.vis/picture">
    <?php echo $naitik['name']; ?>
  </body>
</html>

解决方法:

如果没有用户登录,Facebook用户可以返回0.
您拥有用户的情况意味着您有一个用户通过您的应用程序登录到Facebook.
这也并不意味着您有权查看用户的详细信息.试试我前段时间写的这个简单例子,但仍然有用.

现在注意这是一个重定向控制器.如您所见,它只检查并询问用户.将它用作“中间”控制器,并使用JSFBSDK创建模板化HTML逻辑,或者每当您需要用户将操作重定向到此处时(例如登录等)

// 0. We don't need to clear session
require_once realpath(dirname(__FILE__)) . 'facebook.php';

$current_url = ''; // replace

$facebook = new Facebook(array(
    'appId' => '',
    'secret' => '',
));

$fbCurrentUserID = $facebook->getUser();

// 1. If we cant get the user log him in and request permissions This requests combined permissions (basic + post)
if (!$fbCurrentUserID){
    $loginUrl = $facebook->getLoginUrl(array(
        'scope' => 'email, publish_actions', // Put the permissions you like            
        'redirect_uri' => $current_url, // Replace here
    ));
    die(header('Location: ' . $loginUrl));
}

// 2. So we do have a current FB user. Lets try to read data (Maybe he declined perms)
try {

    $user_profile = $facebook->api('/me');

} catch (FacebookApiException $e) {
    // 2.b Log any error and retry please

    die(header('Location: /'));
}

//Continue your code execution here after all up above went well

标签：php,facebook,facebook-php-sdk
来源： https://codeday.me/bug/20190708/1406766.html

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facebook sdk php示例无效